#include using namespace std; typedef signed long long ll; #define _P(...) (void)printf(__VA_ARGS__) #define FOR(x,to) for(x=0;x<(to);x++) #define FORR(x,arr) for(auto& x:arr) #define FORR2(x,y,arr) for(auto& [x,y]:arr) #define ALL(a) (a.begin()),(a.end()) #define ZERO(a) memset(a,0,sizeof(a)) #define MINUS(a) memset(a,0xff,sizeof(a)) template bool chmax(T &a, const T &b) { if(a bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;} //------------------------------------------------------- int N,Q; vector E[200005]; int P[21][200005],D[200005]; int L[202020],R[202020],id; void dfs(int cur) { L[cur]=id++; sort(ALL(E[cur])); FORR(e,E[cur]) if(e!=P[0][cur]) D[e]=D[cur]+1, P[0][e]=cur, dfs(e); R[cur]=id; } int getpar(int cur,int up) { int i; FOR(i,20) if(up&(1<D[bb]) swap(aa,bb); for(i=19;i>=0;i--) if(D[bb]-D[aa]>=1<=0;i--) if(P[i][aa]!=P[i][bb]) aa=P[i][aa], bb=P[i][bb]; return (aa==bb)?aa:P[0][aa]; // vertex } void solve() { int i,j,k,l,r,x,y; string s; cin>>N>>Q; FOR(i,N-1) { cin>>x>>y; E[x-1].push_back(y-1); E[y-1].push_back(x-1); } //0以外を根にするならP[0][root]=rootが必要 dfs(0); FOR(i,19) FOR(x,N) P[i+1][x]=P[i][P[i][x]]; while(Q--) { cin>>x>>y; x--,y--; if(D[x]%2!=D[y]%2) { cout<<0<