#include<iostream>
#include<algorithm>
#include <atcoder/all>
using namespace std;
using namespace atcoder;
using mint2 = modint998244353;
using ll = long long;

vector<mint2> rev(vector<mint2>& f, ll mod) {
  vector<mint2> res = { mint2(1) / f[0] };
  ll t = 1;
  while (t < mod) {
    t *= 2;
    auto m = convolution(res, res);
    m = convolution(m, f);
    vector<mint2> nres(t);
    for (ll i = 0; i < t; i++) {      
      if (i < res.size())
        nres[i] += 2 * res[i];
      if (i < m.size())
        nres[i] += -m[i];
    }
    res = nres;
  }
  return res;
}


vector<mint2> div(vector<mint2>& f, vector<mint2>& g) {
  auto rf = f;
  auto rg = g;
  reverse(rf.begin(), rf.end());
  reverse(rg.begin(), rg.end());
  ll siz = f.size() - g.size() + 1;
  auto q = convolution(rf, rev(rg, siz));
  q.resize(siz);
  reverse(q.begin(), q.end());
  auto gq = convolution(g, q);
  auto res = f;
  for (ll i = 0; i < res.size(); i++) {    
    if (i < gq.size())
      res[i] -= gq[i];
  }
  while (res.back() == 0 && res.size() > 1)
    res.pop_back();
  return res;
}

ll n;
vector<ll> a;

mint2 solve2(ll l1, ll l2, ll d) {
  ll m = 1;
  while (m < d) {
    m *= 2;
  }
  vector<ll> a1(d), a2(d);
  for (ll i = 0; i < d; i++) {    
    a1[i] = a[l1 + i];
    a2[i] = a[l2 + i];
  }
  vector<mint2> def = { 1 };
  vector<vector<mint2>> f1(m * 2, def), f2(m * 2, def);
  for (ll i = 0; i < d; i++) {
    f1[i + m] = { a1[i],-1 };
    f2[i + m] = { a2[i],-1 };
  }
  for (ll i = m - 1; i >= 1; i--) {
    f1[i] = convolution(f1[i * 2], f1[i * 2 + 1]);
    f2[i] = convolution(f2[i * 2], f2[i * 2 + 1]);
  }
  f1[1] = div(f1[1], f2[1]);
  for (ll i = 2; i < 2 * m; i++) {
    auto& p = f1[i / 2];
    if (f2[i].size() != 1)
      f1[i] = div(p, f2[i]);
  }

  mint2 res = 1;
  for (ll i = 0; i < d; i++)
    res *= f1[i + m][0];
  return res;
}

mint2 solve(ll l, ll r) {
  if (l >= r - 1)
    return 1;
  mint2 res = 1;
  ll d = (r - l) / 2;
  res *= solve2(l, r - d, d);
  res *= solve(l, r - d);
  res *= solve(l + d, r);
  return res;
}

void solve() {
}


int main() {
  cin >> n;
  a.resize(n);
  for (ll i = 0; i < n; i++)
    cin >> a[i];
  mint2 ans = 1;
  cout << solve(0, n).val();
  return 0;
}