#include <algorithm>
#include <cmath>
#include <cstring>
#include <iostream>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <vector>
#include <iterator>

#define pb push_back
#define puts(x) cout << #x << " : " << x << endl;
#pragma GCC diagnostic ignored "-Wconversion"

#define REP(i,n) for (int i=0;i<(n);i++)
#define REPE(i,n) for (int i=0;i<=(n);i++)

#define init(a,b) memset((a), (b), (sizeof(a)));

#define PI 3.14159265
#define EPS (1e-10)
#define EQ(a,b) (abs((a)-(b)) < EPS)

using namespace std;

typedef long long ll;
typedef pair<int, int> P;

int a[1600],b[1600];

map<int, priority_queue<int, vector<int>, greater<int> > > level_times;

int main() {
    int n;
    cin>>n;
    for(int i=0;i<n;i++){
        cin>>a[i];
    }
    for(int i=0;i<n;i++)cin>>b[i];

    map<int, priority_queue<int, vector<int>, greater<int> > > level_times;
    for(int i=0;i<n;i++){
        level_times[a[i]].push(0);
    }

    int mx = 0;

    for(int i=0;i<n;i++){
        map<int, priority_queue<int, vector<int>, greater<int> > > level_times;
        for(int j=0;j<n;j++){
            level_times[a[j]].push(0);
        }
        for(int j=0;j<n;j++){
            int idx = (i+j) % n;

            int level = level_times.begin()->first;

            int times = level_times[level].top();
            level_times[level].pop();
            if(level_times[level].empty()){
                level_times.erase(level);
            }
//            cout<<"********************"<<endl;
//            cout<<b[idx]<<':'<<level<<':'<<times<<endl;
            level += b[idx]/2;
            times += 1;
//            cout<<b[idx]<<':'<<level<<':'<<times<<endl;
//            cout<<"********************"<<endl;
            level_times[level].push(times);
            mx = max(mx, times);
        }
    }

    cout<<mx<<endl;

    return 0;
}