#include #include typedef long long int ll; typedef long double ld; using namespace std; using namespace atcoder; #define inf 1010000000 #define llinf 1001000000000000000ll #define pi 3.141592653589793238 #define rep(i, n) for(ll i = 0; i < (n); i++) #define rep1(i, n) for(ll i = 1; i <= (n); i++) #define rep2(i,l,r) for(ll i = (l); i < (r); i++) #define per(i, n) for(ll i = (n)-1; i >= 0; i--) #define each(x, v) for (auto&& x : v) #define rng(a) a.begin(),a.end() #define fi first #define se second #define pb push_back #define eb emplace_back #define pob pop_back #define st string #define sz(x) (int)(x).size() #define mems(x) memset(x, -1, sizeof(x)); #define pcnt __builtin_popcountll #define _GLIBCXX_DEBUG #define dame { puts("-1"); return 0;} #define yes { puts("Yes"); return 0;} #define no { puts("No"); return 0;} #define ret(x) { cout<<(x)< inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false;} template inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false;} // 仮マクロ 便利だったら昇格 #define dump(x) { cout << #x << " = " << (x) << endl;} #define bit(n) (1LL<<(n)) #define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end()) template inline T in(){ T x; cin >> x; return (x);} #define vcin(x,n) {for(ll loop=0; loop<(n); loop++) cin>>x[loop];} // ここまで仮マクロ // srand((unsigned)time(NULL)); rand()を用いる際にmainの頭に置く // clock()/CLOCKS_PER_SEC 秒数を知りたいときに用いる #define mod 998244353 using mint = modint998244353; /* #define mod 1000000007 using mint = modint1000000007; */ vector dx={1,0,-1,0}; vector dy={0,1,0,-1}; using pl = pair; using ppl = pair; using V = vector; using Graph = vector>; // G.assign(n, vector()); グローバル変数にGを置く時に置く // 関数を置くのはここ以下 // 事前にO(N)で準備、O(1)で取り出す const ll MAX = 200200; vector fac,finv,inv; void binom_init() { fac.resize(MAX); finv.resize(MAX); inv.resize(MAX); fac[0] = fac[1] = 1; inv[1] = 1; finv[0] = finv[1] = 1; for(int i=2; i> n >> s; // 動かせないなら1 ll cnt[3]; rep(i,3) cnt[i] = 0; bool c[3]; rep(i,3) c[i] = false; // 今まででAB,BC,CAが出てきたか bool ans = false; rep(i,n){ int tmp = s[i]-'A'; if(tmp==0){ if(cnt[2]) c[2] = true; if(c[1]) ans = true; cnt[0]++; } if(tmp==1){ if(cnt[0]) c[0] = true; if(c[2]) ans = true; cnt[1]++; } if(tmp==2){ if(cnt[1]) c[1] = true; if(c[0]) ans = true; cnt[2]++; } } if(!ans){ ret(1); return 0; } // 6通り数えて引く mint r; r += fac[n]; rep(i,3) r *= finv[cnt[i]]; r -= n; ret(r.val()) }