// 嘘解法
// 条件 3 を使っていない
// → $2 \leq j \leq M$ かつ $B \leq |K_{S_j} - K_{S_{j-1}}|$

#include <bits/stdc++.h>
using namespace std;
using ll = long long;

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cout << fixed << setprecision(15);

    int N, A, B;
    cin >> N >> A >> B;
    vector<int> X(N), Y(N), K(N);
    for (int i = 0; i < N; i++) { cin >> X[i] >> Y[i] >> K[i]; }

    vector<vector<vector<bool>>> ok(N, vector<vector<bool>>(N, vector<bool>(N)));
    // a -> b -> c
    for (int a = 0; a < N; a++) {
        for (int b = 0; b < N; b++) {
            for (int c = 0; c < N; c++) {
                if (a == b || a == c || b == c) { continue; }
                int d = abs(X[c] - X[a]) + abs(Y[c] - Y[a]) + abs(X[c] - X[b]) + abs(Y[c] - Y[b]);
                // int v = abs(K[c] - K[b]);
                // if (d >= A || v >= B) { ok[a][b][c] = true; }
                if (d >= A) { ok[a][b][c] = true; }
            }
        }
    }

    vector<vector<vector<bool>>> dp(1 << N, vector<vector<bool>>(N, vector<bool>(N)));
    // a -> b
    for (int a = 0; a < N; a++) {
        for (int b = 0; b < N; b++) {
            if (a == b) { continue; }
            int d = abs(X[b] - X[a]) + abs(Y[b] - Y[a]);
            // int v = abs(K[b] - K[a]);
            // if (d >= A || v >= B) { dp[(1 << a) + (1 << b)][a][b] = true; }
            if (d >= A) { dp[(1 << a) + (1 << b)][a][b] = true; }
        }
    }
    for (int S = 1; S < (1 << N); S++) {
        for (int a = 0; a < N; a++) {
            if (((S >> a) & 1) == 0) { continue; }
            for (int b = 0; b < N; b++) {
                if (((S >> b) & 1) == 0) { continue; }
                if (not dp[S][a][b]) { continue; }
                for (int c = 0; c < N; c++) {
                    if (((S >> c) & 1) == 1) { continue; }
                    if (not ok[a][b][c]) { continue; }
                    dp[S + (1 << c)][b][c] = true;
                }
            }
        }
    }

    int ans = 1;
    for (int S = 1; S < (1 << N); S++) {
        for (int a = 0; a < N; a++) {
            for (int b = 0; b < N; b++) {
                if (dp[S][a][b]) {
                    int pcnt = __builtin_popcount(S);
                    ans = max(ans, pcnt);
                }
            }
        }
    }
    cout << ans << '\n';

    return 0;
}