#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using namespace atcoder;
using mint = modint1000000007;
const int mod = 1000000007;
//using mint = modint998244353;
//const int mod = 998244353;
//const int INF = 1e9;
//const long long LINF = 1e18;
#define rep(i, n) for (int i = 0; i < (n); ++i)
#define rep2(i,l,r)for(int i=(l);i<(r);++i)
#define rrep(i, n) for (int i = (n-1); i >= 0; --i)
#define rrep2(i,l,r)for(int i=(r-1);i>=(l);--i)
#define all(x) (x).begin(),(x).end()
#define allR(x) (x).rbegin(),(x).rend()
#define endl "\n"
#define P pair<int,int>
template<typename A, typename B> inline bool chmax(A & a, const B & b) { if (a < b) { a = b; return true; } return false; }
template<typename A, typename B> inline bool chmin(A & a, const B & b) { if (a > b) { a = b; return true; } return false; }
int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	int k, n; cin >> k >> n;
	if (1 == n) {
		if (0 == k)cout << 1 << endl;
		else cout << 0 << endl;
		return 0;
	}
	if (2 == n) {
		cout << 2 << endl;
		return 0;
	}
	vector dp(k + 1, vector<mint>(7));
	dp[0][0] = n - 0;//0,0,0;
	dp[0][1] = n - 1;//0,0,1;
	dp[0][2] = n - 1;//0,1,1;
	dp[0][3] = n - 2;//0,1,2;
	dp[0][4] = n - 1;//1,1,1;
	dp[0][5] = n - 2;//1,1,2;
	dp[0][6] = n - 3;//1,2,3;
	rep2(i, 1, k + 1) {
		dp[i][0] += dp[i - 1][1] * dp[i - 1][1] * dp[i - 1][1] * n;

		dp[i][1] += dp[i - 1][3] * dp[i - 1][3] * dp[i - 1][1] * (n - 1);
		dp[i][1] += dp[i - 1][2] * dp[i - 1][2] * dp[i - 1][1];

		dp[i][2] += dp[i - 1][5] * dp[i - 1][3] * dp[i - 1][3] * (n - 1);
		dp[i][2] += dp[i - 1][4] * dp[i - 1][2] * dp[i - 1][2];

		dp[i][3] += dp[i - 1][2] * dp[i - 1][5] * dp[i - 1][3] * 2;
		dp[i][3] += dp[i - 1][3] * dp[i - 1][3] * dp[i - 1][6] * (n - 2);

		dp[i][4] += dp[i - 1][4] * dp[i - 1][4] * dp[i - 1][4];
		dp[i][4] += dp[i - 1][5] * dp[i - 1][5] * dp[i - 1][5] * (n - 1);

		dp[i][5] += dp[i - 1][4] * dp[i - 1][5] * dp[i - 1][5];
		dp[i][5] += dp[i - 1][5] * dp[i - 1][5] * dp[i - 1][5];
		dp[i][5] += dp[i - 1][5] * dp[i - 1][6] * dp[i - 1][6] * (n - 2);

		dp[i][6] += dp[i - 1][5] * dp[i - 1][5] * dp[i - 1][6] * 3;
		dp[i][6] += dp[i - 1][6] * dp[i - 1][6] * dp[i - 1][6] * (n - 3);
	}
	cout << dp[k][0].val() << endl;
	return 0;
}