#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define FORR2(x,y,arr) for(auto& [x,y]:arr)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
template<class T> bool chmax(T &a, const T &b) { if(a<b){a=b;return 1;}return 0;}
template<class T> bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;}
//-------------------------------------------------------

const int mo=998244353;

int N;
vector<ll> F[5010],G[5010];
int Q;

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N;
	F[0].resize(N+1);
	G[0].resize(N+1);
	F[0][0]=G[0][0]=1;
	FOR(i,N) {
		cin>>x;
		F[i+1]=F[i];
		G[i+1]=G[i];
		for(j=1;j<=N;j++) {
			(F[i+1][j]+=F[i][j-1]*x)%=mo;
			(G[i+1][j]+=G[i+1][j-1]*(-x))%=mo;
		}
		FORR(f,F[i+1]) f=(f%mo+mo)%mo;
		FORR(f,G[i+1]) f=(f%mo+mo)%mo;
	}
	
	cin>>Q;
	while(Q--) {
		int A,B,K;
		cin>>A>>B>>K;
		ll ret=0;
		for(i=0;i<=K;i++) (ret+=F[B][i]*G[A-1][K-i])%=mo;
		cout<<ret<<endl;
	}
	
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}