// とりあえず TLE 解 #include using namespace std; typedef long long ll; typedef pair pii; typedef pair pll; const ll mod = 1e9 + 7; int N; string s; vector> G; // first: ww second: w pll dfs(int v, int p) { pll ret; if (s[v] == 'w') ret.second = 1; for (int ch : G[v]) if (ch != p) { pll tmp = dfs(ch, v); ret.first += tmp.first; ret.second += tmp.second; if (s[v] == 'w') ret.first += tmp.second; } return ret; } signed main() { std::ios::sync_with_stdio(false); std::cin.tie(0); cin >> N; cin >> s; for (int i = 0; i < N; i++) assert(s[i] == 'c' || s[i] == 'w'); G.resize(N); for (int i = 0; i < N-1; i++) { int a, b; cin >> a >> b; a--; b--; G[a].emplace_back(b); G[b].emplace_back(a); } // すべての c から木DP ll ans = 0; for (int i = 0; i < N; i++) { if (s[i] == 'c') { pll tmp = dfs(i, -1); ans += tmp.first; } } cout << ans << endl; }