P = gets.to_i
a = Array.new(P + 1)
(P + 1).times{|i|
    a[i] = Array.new(9 * P + 1, 0)
    }

a[0][0] = 1
ans1 = ans2 = 0
1.upto(P){|i|
    10.times{|x|
        if x == 3
            next
        end
        0.upto(9 * i - x){|j|
            a[i][j + x] += a[i - 1][j]
            }
        }
    ans2 = 9 * ans2 + 10 ** (i - 1)
    ans1 = 0
    3.step(9 * i, 3){|x|
        ans1 += a[i][x]
        }
    }
p ans1 + ans2