#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define FORR2(x,y,arr) for(auto& [x,y]:arr)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
template<class T> bool chmax(T &a, const T &b) { if(a<b){a=b;return 1;}return 0;}
template<class T> bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;}
//-------------------------------------------------------

int N,M,K;
int S[2020],A[2020],B[2020];
const ll mo=998244353;

ll dp[2020][2020];
ll dpS[2020][2020];

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N>>M>>K;
	FOR(i,N) {
		cin>>S[i];
		S[i]--;
	}
	FOR(i,M) cin>>A[i];
	FOR(i,M) cin>>B[i];
	
	dp[0][0]=1;
	dpS[0][0]=1;
	int pre[2020]={};
	for(i=1;i<=N;i++) {
		x=pre[S[i-1]];
		pre[S[i-1]]=i;
		
		FOR(j,K) {
			ll a=dpS[i-1][j];
			if(x) a+=mo-dpS[x-1][j];
			if(j+A[S[i-1]]<=K) (dp[i][j+A[S[i-1]]]+=a)%=mo;
			if(j+B[S[i-1]]<=K) (dp[i][j+B[S[i-1]]]+=a)%=mo;
		}
		
		FOR(j,K+1) dpS[i][j]=(dpS[i-1][j]+dp[i][j])%mo;
	}
	cout<<dpS[N][K]<<endl;
	
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}