// O((A_max)^2)解法
// 入力制約: 0 <= n <= 10^13, 0 < a_i <= 10^5, 0 <= b_i, b_max * floor(n / a_min) <= 2^61
fn solve(n: u64, mut ab: [(u64, u64); 3]) -> u64 {
    let (a_min, a_max, _b_min, b_max) = ab.iter().fold((!0u64, 0u64, !0u64, 0u64), |(a_min, a_max, b_min, b_max), &(a, b)| (a.min(a_min), a.max(a_max), b.min(b_min), b.max(b_max)));
    assert!(n <= 10_0000_0000_0000);
    assert!(a_min > 0 && a_max <= 100000 && b_max.saturating_mul(n / a_min) <= (1u64 << 61));
    
    if ab[1].0 * ab[0].1 < ab[0].0 * ab[1].1 {
    	ab.swap(0, 1);
    }
    if ab[2].0 * ab[0].1 < ab[0].0 * ab[2].1 {
    	ab.swap(0, 2);
    }
    let [(a1, b1), (a2, b2), (a3, b3)] = ab;
    let (a1b2, a1b3) = (a1 * b2.max(1), a1 * b3.max(1));
    let (mut r, mut p, mut s) = (0, 0, n);
    while p < a1b2 {
    	let (mut q, mut t) = (0, s);
        while q < a1b3 {
            r.chmax(t / a1 * b1 + p + q);
			if let Some(d) = t.checked_sub(a3) {
				t = d;
				q += b3;
			} else {
				break;
			}
        }
        if let Some(d) = s.checked_sub(a2) {
        	s = d;
        	p += b2;
        } else {
        	break;
        }
    }
	r
}

fn main() {
    let mut stdinlock = std::io::stdin().lock();
    let mut lines = std::io::BufRead::lines(&mut stdinlock).map_while(Result::ok);
	let n = lines.next().unwrap().parse::<u64>().unwrap();
    let mut ab = [(0u64, 0u64); 3];
    for e in ab.iter_mut() {
		let s = lines.next().unwrap();
		let mut t = s.split_whitespace();
		*e = (
            t.next().unwrap().parse::<u64>().unwrap(),
            t.next().unwrap().parse::<u64>().unwrap(),
		);
    }
    println!("{}", solve(n, ab));
}

trait Change {
    fn chmax(&mut self, x: Self);
    fn chmin(&mut self, x: Self);
}
impl<T: PartialOrd> Change for T {
    fn chmax(&mut self, x: T) {
        if *self < x {
            *self = x;
        }
    }
    fn chmin(&mut self, x: T) {
        if *self > x {
            *self = x;
        }
    }
}