#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using namespace atcoder;
//using mint = modint1000000007;
//const int mod = 1000000007;
using mint = modint998244353;
const int mod = 998244353;
//const int INF = 1e9;
//const long long LINF = 1e18;
#define rep(i, n) for (int i = 0; i < (n); ++i)
#define rep2(i,l,r)for(int i=(l);i<(r);++i)
#define rrep(i, n) for (int i = (n-1); i >= 0; --i)
#define rrep2(i,l,r)for(int i=(r-1);i>=(l);--i)
#define all(x) (x).begin(),(x).end()
#define allR(x) (x).rbegin(),(x).rend()
#define endl "\n"
#define P pair<int,int>
template<typename A, typename B> inline bool chmax(A & a, const B & b) { if (a < b) { a = b; return true; } return false; }
template<typename A, typename B> inline bool chmin(A & a, const B & b) { if (a > b) { a = b; return true; } return false; }
// combination mod prime
// https://www.youtube.com/watch?v=8uowVvQ_-Mo&feature=youtu.be&t=1619
struct combination {
	vector<mint> fact, ifact;
	combination(int n) :fact(n + 1), ifact(n + 1) {
		assert(n < mod);
		fact[0] = 1;
		for (int i = 1; i <= n; ++i) fact[i] = fact[i - 1] * i;
		ifact[n] = fact[n].inv();
		for (int i = n; i >= 1; --i) ifact[i - 1] = ifact[i] * i;
	}
	mint operator()(int n, int k) { return com(n, k); }
	mint com(int n, int k) {
		//負の二項係数を考慮する場合にコメントアウトを外す
		//if (n < 0) return com(-n, k) * (k % 2 ? -1 : 1);
		if (k < 0 || k > n) return 0;
		return fact[n] * ifact[k] * ifact[n - k];
	}
	mint comsub(long long n, long long k) {
		if (n - k < k) k = n - k;
		assert(k < (int)fact.size());
		mint val = ifact[k];
		rep(i, k) val *= n - i;
		return val;
	}
	mint div(int x) {
		if (x >= (int)fact.size())return mint(x).inv();
		return fact[x - 1] * ifact[x];
	}
	mint inv(int n, int k) {
		//if (n < 0) return inv(-n, k) * (k % 2 ? -1 : 1);
		if (k < 0 || k > n) return 0;
		return ifact[n] * fact[k] * fact[n - k];
	}
	mint p(int n, int k) { return fact[n] * ifact[n - k]; }
}c(2000006);
int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	int n, m, k; cin >> n >> m >> k;
	vector<int>s(n), a(m), b(m);
	rep(i, n)cin >> s[i], s[i]--;
	rep(i, m)cin >> a[i];
	rep(i, m)cin >> b[i];
	vector dp(n + 1, vector<mint>(k + 1));
	dp[0][0] = 1;
	vector sdp(n + 2, vector<mint>(k + 1));
	sdp[1][0] = 1;
	vector<int>pre(m);
	rep(i, n) {
		rep(j, k + 1) {
			if (j - a[s[i]] >= 0) {
				dp[i + 1][j] += sdp[i + 1][j - a[s[i]]] - sdp[pre[s[i]]][j - a[s[i]]];
			}
			if (j - b[s[i]] >= 0) {
				dp[i + 1][j] += sdp[i + 1][j - b[s[i]]] - sdp[pre[s[i]]][j - b[s[i]]];
			}
			sdp[i + 2][j] = sdp[i + 1][j] + dp[i + 1][j];
		}
		pre[s[i]] = i + 1;
	}
	mint ans = 0;
	rep(i, n + 1)ans += dp[i][k];
	cout << ans.val() << endl;
	return 0;
}