#include #pragma GCC optimize("Ofast") #pragma GCC optimize("unroll-loops") using namespace std; using std::cout; using std::cin; using std::endl; using ll=long long; using ld=long double; const ll ILL=2167167167167167167; const int INF=2100000000; const int mod=998244353; #define rep(i,a,b) for (int i=(int)a;i<(int)b;i++) #define all(p) p.begin(),p.end() template using _pq = priority_queue, greater>; template ll LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template ll UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,const T &b){if(a>b){a=b;return 1;}else return 0;} template bool chmax(T &a,const T &b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} void yneos(bool a){if(a) cout<<"Yes\n"; else cout<<"No\n";} template void vec_out(vector &p){for(int i=0;i<(int)(p.size());i++){if(i) cout<<" ";cout< T vec_min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T vec_max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T vec_sum(vector &a){assert(!a.empty());T ans=a[0]-a[0];for(auto &x:a) ans+=x;return ans;} int pop_count(long long a){int res=0;while(a){res+=(a&1),a>>=1;}return res;} void solve(); // oddloop int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t=1; //cin>>t; rep(i,0,t) solve(); } void solve(){ int N,M; cin>>N>>M; struct point{ ll x; ll y; }; auto f=[&](point a,point b,point c,point d)->bool{ ll A=a.y-b.y; ll B=b.x-a.x; ll C=-(a.x*A+a.y*B); ll tmp=1; tmp*=(A*c.x+B*c.y+C); tmp*=(A*d.x+B*d.y+C); return tmp>=0; }; auto g=[&](point a,point b,point c,point d)->bool{ return f(a,b,c,d)&f(c,d,a,b); }; auto hoj=[&](ll a)->ll{ return a*a; }; auto dist=[&](point a,point b)->ld{ return sqrtl(hoj(a.x-b.x)+hoj(a.y-b.y)); }; vector p(N*2); rep(i,0,N) rep(j,0,2){ int ind=i+j*N; cin>>p[ind].x>>p[ind].y; } vector G(N*2,vector(N*2,INF)); rep(i,0,N*2) G[i][i]=0; rep(i,0,N*2) rep(j,i+1,N*2){ bool ok=1; rep(k,0,N){ if(!g(p[i],p[j],p[k],p[k+N])) ok=0; } if(ok){ //cout<>a>>b>>c>>d; a--,b--,c--,d--; a+=N*b; c+=N*d; //cout<