#include using namespace std; #define fast_io ios::sync_with_stdio(false); cin.tie(nullptr); #pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math") typedef long long ll; typedef long double ld; #define chmin(a,b) a = min(a,b); #define chmax(a,b) a = max(a,b); #define bit_count(x) __builtin_popcountll(x) #define leading_zero_count(x) __builtin_clz(x) #define trailing_zero_count(x) __builtin_ctz(x) #define gcd(a,b) __gcd(a,b) #define lcm(a,b) a / gcd(a,b) * b #define rep(i,n) for(int i = 0 ; i < n ; i++) #define rrep(i,a,b) for(int i = a ; i < b ; i++) #define repi(it,S) for(auto it = S.begin() ; it != S.end() ; it++) #define pt(a) cout << a << endl; #define debug(a) cout << #a << " " << a << endl; #define all(a) a.begin(), a.end() #define endl "\n"; #define v1(n,a) vector(n,a) #define v2(n,m,a) vector>(n,v1(m,a)) #define v3(n,m,k,a) vector>>(n,v2(m,k,a)) #define v4(n,m,k,l,a) vector>>>(n,v3(m,k,l,a)) templateistream &operator>>(istream&is,pair&p){is>>p.first>>p.second;return is;} templateostream &operator<<(ostream&os,const pair&p){os<istream &operator>>(istream&is,vector&v){for(T &in:v){is>>in;}return is;} templateostream &operator<<(ostream&os,const vector&v){for(auto it=v.begin();it!=v.end();){os<<*it<<((++it)!=v.end()?" ":"");}return os;} templateistream &operator>>(istream&is,vector>&v){for(T &in:v){is>>in;}return is;} templateostream &operator<<(ostream&os,const vector>&v){for(auto it=v.begin();it!=v.end();){os<<*it<<((++it)!=v.end()?"\n":"");}return os;} templateostream &operator<<(ostream&os,const set&v){for(auto it=v.begin();it!=v.end();){os<<*it<<((++it)!=v.end()?" ":"");}return os;} templateostream &operator<<(ostream&os,const multiset&v){for(auto it=v.begin();it!=v.end();){os<<*it<<((++it)!=v.end()?" ":"");}return os;} template struct SegmentTree{ int n , n_; vector dat; vector> range; SegmentTree(int _n){ n = 1 ; n_ = _n ; while(n < _n) n *= 2; dat.resize(2 * n - 1,0); range.resize(2 * n - 1); range[0] = {0,n}; for(int i = 0 ; i < n - 1 ; i++){ auto [l,r] = range[i]; range[2*i+1] = {l,l+(r-l)/2}; range[2*i+2] = {l+(r-l)/2,r}; } } void add(int k , T x){ k += n - 1 ; dat[k] += x ; while(k > 0){ k = (k - 1) / 2 ; dat[k] = dat[2*k+1] + dat[2*k+2] ; } } T sub_query(int a , int b , int k , int l , int r){ if(r <= a || b <= l) return 0 ; if(a <= l && r <= b) return dat[k] ; T lef = sub_query(a,b,2*k+1,l,(l+r)/2) ; T rig = sub_query(a,b,2*k+2,(l+r)/2,r) ; return lef + rig ; } T query(int a , int b){ return sub_query(a,b,0,0,n) ; } }; void solve(){ ll n, m; cin >> n >> m; vector P(n); cin >> P; rep(i,n) P[i]--; ll sum = 0; SegmentTree segtree(n); rep(i,n){ sum += i - segtree.query(0,P[i]); segtree.add(P[i],1); } if(sum == 0){ pt(0) return; } if(m % 2 == 0){ if(sum % 2 != m % 2){ pt(-1) return; } if(m > sum){ pt(m) return; } pt((sum / m + (sum % m != 0)) * m) return; } if(m % 2 != sum % 2) m *= 2; if(m > sum){ pt(m) return; } pt((sum / m + (sum % m != 0)) * m) } int main(){ fast_io int t = 1; // cin >> t; rep(i,t) solve(); }