#include using namespace std; #include using namespace atcoder; using ll = long long; using vll = vector; using vvll = vector; using vvvll = vector; using vd = vector; using vvd = vector; using vvvd = vector; using vb = vector; using vvb = vector; using vvvb = vector; #define all(A) A.begin(),A.end() #define rep(i, n) for (ll i = 0; i < (ll) (n); i++) template bool chmax(T& p, T q, bool C = 1) { if (C == 0 && p == q) { return 1; } if (p < q) { p = q; return 1; } else { return 0; } } template bool chmin(T& p, T q, bool C = 1) { if (C == 0 && p == q) { return 1; } if (p > q) { p = q; return 1; } else { return 0; } } ll modPow(long long a, long long n, long long p) { if (n == 0) return 1; // 0乗にも対応する場合 if (n == 1) return a % p; if (n % 2 == 1) return (a * modPow(a, n - 1, p)) % p; long long t = modPow(a, n / 2, p); return (t * t) % p; } ll gcd(ll(a), ll(b)) { if (a == 0)return b; if (b == 0)return a; ll c = a; while (a % b != 0) { c = a % b; a = b; b = c; } return b; } ll sqrtz(ll N) { ll L = 0; ll R = sqrt(N) + 10000; while (abs(R - L) > 1) { ll mid = (R + L) / 2; if (mid * mid <= N)L = mid; else R = mid; } return L; } using mint = modint998244353; using vm = vector; using vvm = vector; using vvvm = vector; using vvvvm = vector; using vvvvvm = vector; using vvvvvvm = vector; vector fact, factinv, inv; const ll mod = 998244353; void prenCkModp(ll n) { fact.resize(n + 5); factinv.resize(n + 5); inv.resize(n + 5); fact[0] = fact[1] = 1; factinv[0] = factinv[1] = 1; inv[1] = 1; for (ll i = 2; i < n + 5; i++) { fact[i] = (fact[i - 1] * i); inv[i] = (mod - ((inv[mod % i] * (mod / i)))); factinv[i] = (factinv[i - 1] * inv[i]); } } mint nCk(ll n, ll k) { if (n < k || k < 0) return 0; return (fact[n] * ((factinv[k] * factinv[n - k]))); } int main() { cin.tie(nullptr); ios::sync_with_stdio(false); ll N, M, K; string S; cin >> N >> M >> K >> S; vb U(26, 0); vvvm DP(M + 1, vvm(27, vm(2, 0))); DP[0][0][1] = 1; vvm EP(27,vm(2,0)); EP[0][1]=1; mint an = 0; rep(i, N) { vvm NEP(27,vm(2,0)); rep(k, 27) { NEP[k][0] += EP[k][0] * k; if (k != 26)NEP[k + 1][0] += EP[k][0] * (26 - k); ll d = S[i] - 'a'; if (U[d]) { NEP[k][1] += EP[k][1]; } else { if (k != 26)NEP[k + 1][1] += EP[k][1]; } rep(j, d) { if (!U[j]) { if (k != 26)NEP[k + 1][0] += EP[k][1]; } else { NEP[k][0] += EP[k][1]; } } } EP=NEP; rep(k,27){ if(k>=K){ an+=EP[k][0]; if(i=K)an+=DP[i+N+1][k][0]; } EP=NEP; rep(k,27){ if(k>=K){ an+=EP[k][0]; //if(i=K)an+=DP[M][k][0]; cout << an.val() << endl; }