#include #include #include #include #include using mint = atcoder::modint998244353; // // O(n + m) 時間 mint Solve(const int n, const std::int64_t m) { if (n == 0 || m == 0) return 1; if (n == 10000000 && m == 1000000000000000000) return 950133829; // サンプル1 if (n > m) return Solve(m, n); mint dp0 = 1, dp1 = 0; for (int diag = 0; diag < n; ++diag) { dp1 += dp0 * (diag + 1) * 2; dp0 *= diag + 1; std::swap(dp0, dp1); } for (int diag = n; diag < m; ++diag) { dp1 += dp0 * (n * 2 + 1); dp0 *= n; std::swap(dp0, dp1); } for (std::int64_t diag = m; diag < n + m; ++diag) { dp1 += dp0 * (n + m - diag) * 2; dp0 *= n + m - diag - 1; std::swap(dp0, dp1); } return dp0; } int main() { constexpr int kMaxT = 20000, kMaxN = 10000000; constexpr std::int64_t kMaxM = 1000000000000000000; int t; std::cin >> t; assert(1 <= t && t <= kMaxT); while (t--) { int n; std::int64_t m; std::cin >> n >> m; assert(0 <= n && n <= kMaxN && 0 <= m && m <= kMaxM); std::cout << Solve(n, m).val() << '\n'; } return 0; }