// TLE: x 全探索

#include <array>
#include <cassert>
#include <iostream>
#include <limits>
#include <tuple>
#include <vector>

long long floor_pow2(long long n) {
    long long x = 1;
    while ((x << 1) <= n) x <<= 1;
    return x;
}

using Weight = long long;

constexpr int L = 30;

constexpr Weight inf = std::numeric_limits<int>::max();

long long solve(int n, int m, const std::vector<long long>& r, const std::vector<long long>& c, const std::vector<std::vector<long long>>& a) {
    for (int i = 0; i < n; ++i) for (int j = 0; j < m; ++j) {
        if (a[0][0] ^ a[0][j] ^ a[i][0] ^ a[i][j]) {
            return -1;
        }
    }

    int bit_num = 0;
    for (int i = 0; i < n; ++i) for (int j = 0; j < m; ++j) {
        bit_num = std::max(bit_num, __builtin_ctzll(floor_pow2(a[i][j])) + 1);
    }

    std::pair<Weight, long long> min_cost{ inf, 0 };

    for (long long x = 0; x < 1LL << bit_num; ++x) {
        Weight cost = 0;
        for (int i = 0; i < n; ++i) {
            long long s = x ^ a[i][0] ^ a[0][0];
            if (s == 0) {
                continue;
            } else if (s <= r[i]) {
                cost += 1;
            } else {
                if (r[i] == 0 or s >= 2 * floor_pow2(r[i])) {
                    cost += inf;
                } else {
                    cost += 2;
                }
            }
        }
        for (int j = 0; j < m; ++j) {
            long long t = x ^ a[0][j];
            if (t == 0) {
                continue;
            } else if (t <= c[j]) {
                cost += 1;
            } else {
                if (c[j] == 0 or t >= 2 * floor_pow2(c[j])) {
                    cost += inf;
                } else {
                    cost += 2;
                }
            }
        }
        min_cost = std::min(min_cost, std::pair{ cost, x });
    }

    auto [cost, X] = min_cost;

    if (cost >= inf) {
        return -1;
    }

    return cost;
}

int main() {
    std::ios::sync_with_stdio(false);
    std::cin.tie(nullptr);

    int t;
    std::cin >> t;

    while (t-- > 0) {
        int n, m;
        std::cin >> n >> m;

        std::vector<long long> r(n), c(m);
        for (auto& e : r) std::cin >> e;
        for (auto& e : c) std::cin >> e;

        std::vector a(n, std::vector<long long>(m));
        for (auto& row : a) for (auto& e : row) {
            std::cin >> e;
        }

        std::cout << solve(n, m, r, c, a) << '\n';
    }

    return 0;
}