#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using namespace atcoder;
using ll = long long;
using P = pair<ll,ll>;
#define rep(i,n) for(int (i)=0;(i)<(n);(i)++)
#define rep2(i,m,n) for(int (i)=(m);(i)<(n);(i)++)
#define rep2ll(i,m,n) for(ll (i)=(m);(i)<(n);(i)++)
#define ALL(obj) (obj).begin(), (obj).end()
#define rALL(obj) (obj).rbegin(), (obj).rend()
const ll INF60 = 1LL<<60;//1152921504606846976
const int INF30 = 1<<30;
using mint = modint998244353;
using VL = vector<ll>;
using VVL = vector<VL>;
using VVVL = vector<VVL>;
using VM = vector<mint>;
using VVM = vector<VM>;
using VVVM = vector<VVM>;
using VD = vector<double>;
using VVD = vector<VD>;
using VVVD = vector<VVD>;
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }

template< typename T >
struct Combination {
  vector< T > _fact, _rfact, _inv;

  Combination(int sz) : _fact(sz + 1), _rfact(sz + 1), _inv(sz + 1) {
    _fact[0] = _rfact[sz] = _inv[0] = 1;
    for(int i = 1; i <= sz; i++) _fact[i] = _fact[i - 1] * i;
    _rfact[sz] /= _fact[sz];
    for(int i = sz - 1; i >= 0; i--) _rfact[i] = _rfact[i + 1] * (i + 1);
    for(int i = 1; i <= sz; i++) _inv[i] = _rfact[i] * _fact[i - 1];
  }

  inline T fact(int k) const { return _fact[k]; }

  inline T rfact(int k) const { return _rfact[k]; }

  inline T inv(int k) const { return _inv[k]; }

  T P(int n, int r) const {
    if(r < 0 || n < r) return 0;
    return fact(n) * rfact(n - r);
  }

  T C(int p, int q) const {
    if(q < 0 || p < q) return 0;
    return fact(p) * rfact(q) * rfact(p - q);
  }

  T H(int n, int r) const {
    if(n < 0 || r < 0) return (0);
    return r == 0 ? 1 : C(n + r - 1, r);
  }
};


int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);
    ll n, m; cin>>n>>m;
    m = abs(m);
    Combination<mint> c(n);
    mint ans = 0;
    if(m==0){
        if(n%2) ans = 0;
        else ans = c.C(n,n/2)*mint(2).pow(n+1)-c.C(n,n/2).pow(2);
    }else{
        for(ll x=1; x*x<=m; x++){
            if(m%x) continue;
            ll y = m/x;
            if((n+x)%2||(n+y)%2) continue;
            ans += c.C(n,(n+x)/2) * c.C(n,(n+y)/2) * (1+(x!=y));
        }
        ans *= 2;
    }
    // cerr<<ans.val()<<endl;
    cout<<(ans/mint(4).pow(n)).val();
    
    return 0;
}