#include using namespace std; using ll = long long; const ll modc = 998244353; class mint { ll x; public: mint(ll x=0) : x((x%modc+modc)%modc) {} mint operator-() const { return mint(-x); } mint& operator+=(const mint& a) { if ((x += a.x) >= modc) x -= modc; return *this; } mint& operator-=(const mint& a) { if ((x += modc-a.x) >= modc) x -= modc; return *this; } mint& operator*=(const mint& a) { (x *= a.x) %= modc; return *this; } mint operator+(const mint& a) const { mint res(*this); return res+=a; } mint operator-(const mint& a) const { mint res(*this); return res-=a; } mint operator*(const mint& a) const { mint res(*this); return res*=a; } mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } mint inv() const { return pow(modc-2); } mint& operator/=(const mint& a) { return (*this) *= a.inv(); } mint operator/(const mint& a) const { mint res(*this); return res/=a; } bool operator == (const mint& a) const{ return x == a.x; } friend ostream& operator<<(ostream& os, const mint& m){ os << m.x; return os; } friend istream& operator>>(istream& ip, mint &m) { ll t; ip >> t; m = mint(t); return ip; } }; mint a; //sum (i=0 to A) floor(i/B) mint floor_sum(ll A, ll B){ if (A < 0) return 0; ll q = A/B, r = A % B; return mint(B) * (q-1) * q * a + mint(q) * (r+1); } int main(){ int T; cin >> T; ll N, M, L, R; a = mint(2).inv(); while(T){ T--; cin >> N >> M >> L >> R; mint ans = R-L+1; ans += floor_sum(R, N-1); ans -= floor_sum(L-1, N-1); ans += floor_sum(M-L, N-1); ans -= floor_sum(M-R-1, N-1); cout << ans << '\n'; } return 0; }