def Multiple_LCM(A: list) -> int:
    '''
    複数の整数に対する最小公倍数を返す

    Parameters
    ----------
    A:list
    '''
    from collections import defaultdict
    MOD = 998244353
    Exponent = defaultdict(int)
    for a in A:
        primes = []
        for i in range(2, a+1):
            if i*i > a:
                break
            if a % i != 0:
                continue
            cnt = 0
            while a % i == 0:
                cnt += 1
                a //= i
            primes.append((i, cnt))
        if a > 1:
            primes.append((a, 1))
        for p, v in primes:
            Exponent[p] = max(Exponent[p], v)
    res = 1
    for p, exp in Exponent.items():
        res *= pow(p, exp, MOD)
        res %= MOD
    return res


N, M = map(int, input().split())
P = [i for i in range(N)]
for _ in range(M):
    L, *T = list(map(int, input().split()))
    sigma = []
    for t in T:
        sigma.append(P[t-1])
    for i in range(L):
        if i < L-1:
            j = T[i+1]-1
        else:
            j = T[0]-1
        P[j] = sigma[i]
loop = []
seen = [False]*N
for i in range(N):
    if seen[i]:
        continue
    tmp = 1
    seen[i] = True
    next = P[i]
    while not seen[next]:
        seen[next] = True
        tmp += 1
        next = P[next]
    loop.append(tmp)
ans = Multiple_LCM(loop)
print(ans)