#include using namespace std; // https://yukicoder.me/problems/no/2242 /* n个城市,高度分别为h[1],..h[n]. 另给一个长度为n的数组t,从城市i出发,可以到达高度不超过t[i]的所有其他城市, 有q次询问,每次询问给出x,y,求从x到y的最少边数,如果无法到达y,输出-1. + 2 <= n <= 2e5 + 1 <= q <= 2e5 + 1 <= h[i], t[i] <= 1e9 + 1 <= a[i], b[i] <= n + a[i] != b[i] */ using ll = long long; // 预处理 O(NlogN);查询:O(logN) struct BiLifting { int N, INVALID, lgD; vector> mat; BiLifting() : N(0), lgD(0) {} BiLifting(const vector &vec_nxt, int INVALID = -1, int lgd = 0) : N(vec_nxt.size()), INVALID(INVALID), lgD(lgd) { while ((1LL << lgD) < N) lgD++; mat.assign(lgD, vector(N, INVALID)); mat[0] = vec_nxt; for (int i = 0; i < N; i++) if (mat[0][i] < 0 or mat[0][i] >= N) mat[0][i] = INVALID; for (int d = 0; d < lgD - 1; d++) { for (int i = 0; i < N; i++) if (mat[d][i] != INVALID) mat[d + 1][i] = mat[d][mat[d][i]]; } } int kth_next(int now, long long k) { if (k >= (1LL << lgD)) exit(8); for (int d = 0; k and now != INVALID; d++, k >>= 1) if (k & 1) now = mat[d][now]; return now; } // Distance from l to [r, infty) // Requirement: mat[0][i] > i for all i (monotone increasing) int distance(int l, int r) { if (l >= r) return 0; int ret = 0; for (int d = lgD - 1; d >= 0; d--) { if (mat[d][l] < r and mat[d][l] != INVALID) ret += 1 << d, l = mat[d][l]; } if (mat[0][l] == INVALID or mat[0][l] >= r) return ret + 1; else return -1; // Unable to reach } }; template struct Discrete { vector xs; Discrete(const vector& v) { xs = v; sort(xs.begin(), xs.end()); xs.erase(unique(xs.begin(), xs.end()), xs.end()); } int get(const T& x) const { return lower_bound(xs.begin(), xs.end(), x) - xs.begin(); } inline int operator()(const T& x) const { return get(x); } T operator[](int i) { return xs[i]; } int size() const { return xs.size(); } }; int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int n; cin >> n; vector h(n), t(n); for (int &x : h) cin >> x; for (int &x : t) cin >> x; auto z = h; z.insert(z.end(), t.begin(), t.end()); Discrete v(z); for (auto &x : h) x = v(x); for (auto &x : t) x = v(x); int m = v.size(); vector g(m); iota(g.begin(), g.end(), 0); for (int i = 0; i < n; ++i) g[h[i]] = max(g[h[i]], t[i]); for (int i = 1; i < m; ++i) g[i] = max(g[i], g[i - 1]); BiLifting bl(g); int q; cin >> q; for (int i = 0; i < q; ++i) { int x, y; cin >> x >> y; x--, y--; int l = t[x], r = h[y]; auto c = bl.distance(l, r); if (c >= 0) c++; cout << c << '\n'; } return 0; }