#include <iostream>
#include <algorithm>
#include <iomanip>
#include <vector>
#include <queue>
#include <deque>
#include <set>
#include <map>
#include <tuple>
#include <cmath>
#include <numeric>
#include <functional>
#include <cassert>
#include <atcoder/modint>

#define debug_value(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << #x << "=" << x << endl;
#define debug(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << x << endl;

template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

using namespace std;
typedef long long ll;

template<typename T>
vector<vector<T>> vec2d(int n, int m, T v){
    return vector<vector<T>>(n, vector<T>(m, v));
}

template<typename T>
vector<vector<vector<T>>> vec3d(int n, int m, int k, T v){
    return vector<vector<vector<T>>>(n, vector<vector<T>>(m, vector<T>(k, v)));
}

template<typename T>
void print_vector(vector<T> v, char delimiter=' '){
    if(v.empty()) {
        cout << endl;
        return;
    }
    for(int i = 0; i+1 < v.size(); i++) cout << v[i] << delimiter;
    cout << v.back() << endl;
}

using mint = atcoder::modint1000000007;

ostream& operator<<(ostream& os, const mint& m){
    os << m.val();
    return os;
}


int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout << setprecision(10) << fixed;
    int n; cin >> n;
    vector<vector<int>> g(n);
    for(int i = 0; i < n-1; i++){
        int a, b; cin >> a >> b; a--; b--;
        g[a].push_back(b);
        g[b].push_back(a);
    }
    auto dp = vec2d(n, 4, mint(0));
    function<void(int, int)> dfs = [&](int v, int par){
        dp[v][0] = 1;
        dp[v][1] = 1;
        dp[v][2] = mint(2).inv();
        dp[v][3] = mint(6).inv();
        for(int to: g[v]){
            if(to == par) continue;
            dfs(to, v);
            vector<mint> nx(4);
            for(int c0 = 0; c0 <= 3; c0++){
                for(int c1 = 0; c1 <= 3; c1++){
                    if(c0+c1 <= 3){
                        nx[c0+c1] += dp[v][c0]*dp[to][c1];
                    }
                }
            }
            dp[v] = nx;
        }
        dp[v][1] /= 2;
        dp[v][2] /= 2;
    };
    dfs(0, -1);
    mint ans = (dp[0][3]*6)*mint(2).pow(n-1);
    cout << ans << endl;
}