#include using namespace std; //#pragma GCC optimize("Ofast") #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=r-1;i>=l;i--) #define all(x) (x).begin(),(x).end() #define CST(x) cout<> #define rev(x) reverse(x); using ll=long long; using vl=vector; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; const ll MOD=1000000007; const ll MOD9=998244353; const int inf=1e9+10; const ll INF=4e18; const ll dy[9]={1,0,-1,0,1,1,-1,-1,0}; const ll dx[9]={0,1,0,-1,1,-1,1,-1,0}; template inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; } template inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; } //https://atcoder.jp/contests/abc230/submissions/44985883 vector> quotient_floors(ll n){ //floor(n/i)=xを満たすx,i∈[l,r)をこの順に返す。lの昇順、つまりxの降順なことに注意。 vector> ret; for(ll l=1;l<=n;){ ll x=n/l; ll r=n/x+1; ret.emplace_back(x,l,r); l=r; } return ret; } int main(){ ll p,q;cin >> p >> q; auto fs=quotient_floors(p); while(q--){ ll ans=0; ll L,R;cin >> L >>R;R++; for(auto [x,l,r]:fs){ ll lx=max(L,l),rx=min(r,R); if(lx+1>rx)continue; ll ret=(rx-lx)*p-x*(rx+lx-1)*(rx-lx)/2; ans+=(rx-lx)*p-x*(rx+lx-1)*(rx-lx)/2; /*cout << lx <<" " << rx <<" " << x << endl; cout << ret << endl;*/ } ans+=p*max(R-1-p,0LL); cout << ans << endl; } }