#include <bits/stdc++.h>
#define all(x) x.begin(), x.end()
#define MOD 101
using namespace std;
using ll = long long;


ll powmod(ll a, ll n) {
    ll ret = 1;
    while(n){
        if(n & 1){
            ret *= a;
            ret %= MOD;
        }
        n >>= 1;
        a *= a;  a %= MOD;
    }
    return ret;
}
const ll INV2 = powmod(2, MOD - 2);
const ll INV3 = powmod(3, MOD - 2);


ll det(vector<vector<ll> >& P){
    ll ret = 0;
    for(int i = 0; i < 3; ++i){
        ret += P[i][0] * P[(i + 1) % 3][1] * P[(i + 2) % 3][2];
        ret -= P[i][2] * P[(i + 1) % 3][1] * P[(i + 2) % 3][0];
    }
    return ret;
}


char solve(int N, int K, vector<vector<ll> >& P, vector<int>& a, string& s){
    ll d = abs(det(P));
    if(d == 0){
        return 'D';
    }
    vector<vector<vector<int> > > dp(N + 1, vector<vector<int> >(MOD, vector<int>(4, -1)));
    for(int j = 0; j < MOD; ++j){
        dp[N][j][3] = (j >= K) ? 1 : 0;
    }
    for(int i = N - 1; i >= 0; --i){
        bool player_is_koa = (s[i] == 'K');
        int val = a[i] + 1;
        bool val_div2 = (val % 2 == 0), val_div3 = (val % 3 == 0);
        for(int j = 0; j < MOD; ++j){
            for(int k = 0; k < 4; ++k){
                vector<int> results = { dp[i + 1][j][k], dp[i + 1][j * val % MOD][k | val_div2 | (val_div3 << 1)] };
                if(player_is_koa){
                    if(find(all(results), 1) != results.end()){
                        dp[i][j][k] = 1;
                    }
                    else if(find(all(results), -1) != results.end()){
                        dp[i][j][k] = -1;
                    }
                    else{
                        dp[i][j][k] = 0;
                    }
                }
                else{
                    if(find(all(results), 0) != results.end()){
                        dp[i][j][k] = 0;
                    }
                    else if(find(all(results), -1) != results.end()){
                        dp[i][j][k] = -1;
                    }
                    else{
                        dp[i][j][k] = 1;
                    }
                }
            }
        }
    }
    bool div2 = (d % 2 == 0), div3 = (d % 3 == 0);
    int stat_init = dp[0][d % MOD * INV2 * INV3 % MOD][div2 | (div3 << 1)];
    if(stat_init == -1){
        return 'D';
    }
    return (stat_init == 1) ? 'K' : 'P';
}


int main(){
    int t;  cin >> t;

    for(int i = 0; i < t; ++i){
        int N, K;  cin >> N >> K;
        vector<vector<ll> > P(3, vector<ll>(3));
        for(auto& v : P){
            cin >> v[0] >> v[1] >> v[2];
        }
        vector<int> a(N);
        for(auto& x : a){
            cin >> x;
        }
        string s;  cin >> s;
        cout << solve(N, K, P, a, s) << endl;
    }

    return 0;
}