#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;

template <int m>
std::ostream& operator<<(std::ostream& os, const atcoder::static_modint<m>& a) {os << a.val(); return os;}
template<typename T>
istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename T>
ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template <typename T>
ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}

void solve(){
	int n;
	cin >> n;
	vi a(n);
	cin >> a;
	int sum = 0;
	rep(i, n) sum += a[i];
	if(sum != n){
		cout << "No\n";
		return;
	}
	bool all_one = true;
	rep(i, n) if(a[i] != 1) all_one = false;
	if(all_one){
		cout << "No\n";
		return;
	}
	bool success = true;
	rep(i, n) if((a[i] == 0 and a[(i + 1) % n] == 0) or (a[i] == 2 and a[(i + 1) % n] == 2)) success = false;
	if(!success){
		cout << "No\n";
		return;
	}
	cout << "Yes\n";
}

int main(){
	int t;
	cin >> t;
	rep(i, t) solve();
	
	return 0;
}