// #pragma GCC target("avx") // #pragma GCC optimize("O3") // #pragma GCC optimize("unroll-loops") #include using namespace std; #define rep(i,n) for(int i = 0; i < (int)n; i++) #define FOR(n) for(int i = 0; i < (int)n; i++) #define repi(i,a,b) for(int i = (int)a; i < (int)b; i++) #define all(x) x.begin(),x.end() //#define mp make_pair #define vi vector #define vvi vector #define vvvi vector #define vvvvi vector #define pii pair #define vpii vector> template bool chmax(T &a, const T b) {if(a bool chmin(T &a, const T b) {if(a>b) {a=b; return true;} else {return false;}} using ll = long long; using ld = long double; using ull = unsigned long long; const ll INF = numeric_limits::max() / 2; const ld pi = 3.1415926535897932384626433832795028; const ll mod = 998244353; int dx[] = {1, 0, -1, 0, -1, -1, 1, 1}; int dy[] = {0, 1, 0, -1, -1, 1, -1, 1}; #define int long long namespace internal { template struct csr { std::vector start; std::vector elist; explicit csr(int n, const std::vector>& edges) : start(n + 1), elist(edges.size()) { for (auto e : edges) { start[e.first + 1]++; } for (int i = 1; i <= n; i++) { start[i] += start[i - 1]; } auto counter = start; for (auto e : edges) { elist[counter[e.first]++] = e.second; } } }; // Reference: // R. Tarjan, // Depth-First Search and Linear Graph Algorithms struct scc_graph { public: explicit scc_graph(int n) : _n(n) {} int num_vertices() { return _n; } void add_edge(int from, int to) { edges.push_back({from, {to}}); } // @return pair of (# of scc, scc id) std::pair> scc_ids() { auto g = csr(_n, edges); int now_ord = 0, group_num = 0; std::vector visited, low(_n), ord(_n, -1), ids(_n); visited.reserve(_n); auto dfs = [&](auto self, int v) -> void { low[v] = ord[v] = now_ord++; visited.push_back(v); for (int i = g.start[v]; i < g.start[v + 1]; i++) { auto to = g.elist[i].to; if (ord[to] == -1) { self(self, to); low[v] = std::min(low[v], low[to]); } else { low[v] = std::min(low[v], ord[to]); } } if (low[v] == ord[v]) { while (true) { int u = visited.back(); visited.pop_back(); ord[u] = _n; ids[u] = group_num; if (u == v) break; } group_num++; } }; for (int i = 0; i < _n; i++) { if (ord[i] == -1) dfs(dfs, i); } for (auto& x : ids) { x = group_num - 1 - x; } return {group_num, ids}; } std::vector> scc() { auto ids = scc_ids(); int group_num = ids.first; std::vector counts(group_num); for (auto x : ids.second) counts[x]++; std::vector> groups(ids.first); for (int i = 0; i < group_num; i++) { groups[i].reserve(counts[i]); } for (int i = 0; i < _n; i++) { groups[ids.second[i]].push_back(i); } return groups; } private: int _n; struct edge { int to; }; std::vector> edges; }; } // namespace internal struct two_sat { public: two_sat() : _n(0), scc(0) {} explicit two_sat(int n) : _n(n), _answer(n), scc(2 * n) {} void add_clause(int i, bool f, int j, bool g) { assert(0 <= i && i < _n); assert(0 <= j && j < _n); scc.add_edge(2 * i + (f ? 0 : 1), 2 * j + (g ? 1 : 0)); scc.add_edge(2 * j + (g ? 0 : 1), 2 * i + (f ? 1 : 0)); } bool satisfiable() { auto id = scc.scc_ids().second; vector comps(*max_element(all(id))+1); FOR(_n) ++comps[id[2 * i]]; vector order(*max_element(all(id))+1); iota(all(order), 0); sort(all(order), [&](int i, int j) -> bool { return comps[i] < comps[j]; }); // for(auto e : id) cout << e << " "; cout << "\n"; // for(auto e : comps) cout << e << " "; cout << "\n"; // for(auto e : order) cout << e << " "; cout << "\n"; vector inv(*max_element(all(id))+1); FOR(*max_element(all(id))+1) inv[order[i]] = i; for (int i = 0; i < _n; i++) { if (id[2 * i] == id[2 * i + 1]) return false; _answer[i] = inv[id[2 * i]] > inv[id[2 * i + 1]]; } return true; } std::vector answer() { return _answer; } private: int _n; std::vector _answer; internal::scc_graph scc; }; void solve() { int n, m; cin >> n >> m; two_sat sat(n); FOR(m) { int u, v; string s; cin >> u >> s >> v; --u; --v; if(s == "<==>") { sat.add_clause(u, true, v, false); sat.add_clause(u, false, v, true); }else { sat.add_clause(u, true, v, true); sat.add_clause(u, false, v, false); } } bool satisfy = sat.satisfiable(); vector ans = sat.answer(); int sz = (int)count(all(ans), true); if(satisfy && 2*sz >= n) { cout << "Yes" << endl; cout << sz << endl; FOR(n) if(ans[i]) cout << i+1 << " "; cout << "\n"; }else { cout << "No" << endl; } } signed main() { cin.tie(nullptr); ios::sync_with_stdio(false); solve(); return 0; }