#include<iostream>

long long multi(long long num, long long p) {
	if (p == 1) return num;
	if (p % 2 == 0) {
		long long n = multi(num, p / 2);
		return (n + n) % 1000007;
	} else {
		return (multi(num, p - 1) + num) % 1000007;
	}
}

int main() {
	long long n;
	std::cin >> n;

	long long ue = n / 2,
	          shita = n - ue;

	std::cout << (multi((shita + 1), ue) + shita) % 1000007 << std::endl;
	return 0;
}