#緑以下Ex-A

import heapq as hq
N,M = map(int,input().split())

#G[i][x]: xは0なら行き、1なら帰り
G = [[[] for _ in range(2)] for _ in range(N)]
for _ in range(M):
    u,v,t = map(lambda x:int(x)-1,input().split()); t+=1
    G[u][0].append((v,t)); G[v][1].append((u,t))

#dist_1[k]: 町N-2→町k, 町k→町N-2
dist_1 = [[10**18]*2 for _ in range(N)]
Q = [(0,N-2,0),(0,N-2,1)]
while Q:
    time,now,x = hq.heappop(Q)
    if dist_1[now][x] < time: continue
    dist_1[now][x] = time
    for next,cost in G[now][x]:
        if dist_1[next][x] > time + cost:
            hq.heappush(Q,(time+cost, next, x))

#dist_2[k]: 町N-1→町k, 町k→町N-1
dist_2 = [[10**18]*2 for _ in range(N)]
Q = [(0,N-1,0),(0,N-1,1)]
while Q:
    time,now,x = hq.heappop(Q)
    if dist_2[now][x] < time: continue
    dist_2[now][x] = time
    for next,cost in G[now][x]:
        if dist_2[next][x] > time + cost:
            hq.heappush(Q,(time+cost, next, x))

#順に答えを出力
for k in range(N-2):
    ans = 10**18
    ans = min(ans, dist_1[k][1] + dist_1[N-1][0] + dist_2[k][0])
    ans = min(ans, dist_2[k][1] + dist_2[N-2][0] + dist_1[k][0])
    print(ans if ans < 10**18 else -1)