package main import ( "bufio" "fmt" "os" ) func main() { Yuki952() // Yuki705() } // 危险的火药库 // 有n个火药库,每个火药库有一个危险程度A[i]. // 现在需要打开某些火药库. // 总危险程度为 `被打开的火药库连续段的危险程度之和`的平方和. // 对k=1,...,n,求打开k个火药库时的最小总危险程度. // n<=3000, A[i]<=1e6 // https://yukicoder.me/problems/no/952 func Yuki952() { in := bufio.NewReader(os.Stdin) out := bufio.NewWriter(os.Stdout) defer out.Flush() var n int fmt.Fscan(in, &n) nums := make([]int, n) for i := 0; i < n; i++ { fmt.Fscan(in, &nums[i]) } preSum := make([]int, n+1) for i := 0; i < n; i++ { preSum[i+1] = preSum[i] + nums[i] } // 0 -> n+1 的路径 // i -> j 的边权为: (sum_{k=i...j-2} nums[k])^2 cost := func(i, j int) int { if j-i <= 1 { return 0 } tmp := preSum[j-1] - preSum[i] return tmp * tmp } res := EnumerateMongeDEdgeShortestPath(n+1, cost) for k := 1; k <= n; k++ { fmt.Fprintln(out, res[n+1-k]) } } // 清理垃圾 // https://yukicoder.me/problems/no/705 func Yuki705() { in := bufio.NewReader(os.Stdin) out := bufio.NewWriter(os.Stdout) defer out.Flush() var n int fmt.Fscan(in, &n) A := make([]int, n) X := make([]int, n) Y := make([]int, n) for i := 0; i < n; i++ { fmt.Fscan(in, &A[i]) } for i := 0; i < n; i++ { fmt.Fscan(in, &X[i]) } for i := 0; i < n; i++ { fmt.Fscan(in, &Y[i]) } cubic := func(x int) int { return abs(x * x * x) } // 人i,垃圾j dist := func(i, j int) int { return cubic(X[j]-A[i]) + cubic(Y[j]) } f := func(i, j int) int { return dist(j-1, i) } fmt.Fprintln(out, MongeShortestPath(n, f)[n]) } func abs(x int) int { if x < 0 { return -x } return x } const INF int = 1e18 // Monge图最短路.求从0点出发到各个点的最短路. // O(nlogn). // f(i,j) : 边权函数, 即从i到j的边的权值(0<=i= to { return } cost := f(from, to) if tmp := dp[from] + cost; tmp < dp[to] { dp[to] = tmp x[to] = from } } var dfs func(int, int) dfs = func(l, r int) { if l+1 >= r { return } m := (l + r) / 2 for i := x[l]; i <= x[r]; i++ { check(i, m) } dfs(l, m) for i := l + 1; i <= m; i++ { check(i, r) } dfs(m, r) } dp[0] = 0 check(0, n) dfs(0, n) return dp } // Monge图d边最短路. // O(nlogn)求从0到n恰好经过d条边的最短路,其中边权f(from,to)满足Monge性质. // f(i,j) : 边权函数, 即从i到j的边的权值(0<=i n { panic("d > N") } cal := func(x int) int { g := func(frm, to int) int { return f(frm, to) + x } cost := MongeShortestPath(n, g)[n] return cost - x*d } _, res := FibonacciSearch(cal, -3*maxWeight, 3*maxWeight+1, false) return res } // monge图从0到n,经过d边最短路的d=1,...,N的答案. // 无法到达的点的距离为INF. // f(i,j) : 边权函数, 即从i到j的边的权值(0<=i= d; i-- { dp[i] = dp[midx[i]] + f(midx[i], i) } res[d] = dp[n] } return res } // 给定一个 n 行 m 列的矩阵. // minI=argmin_j(A[i][j]) 单调递增时, 返回 minI. // f(i, j, k) : // 比较 A[i][j] 和 A[i][k] (保证 j < k) // 当 A[i][j] <= A[i][k] 时返回 true. func MonotoneMinima(row, col int, f func(i, j, k int) bool) []int { res := make([]int, row) var dfs func(int, int, int, int) dfs = func(is, ie, l, r int) { if is == ie { return } i := (is + ie) / 2 m := l for k := l + 1; k < r; k++ { if !f(i, m, k) { m = k } } res[i] = m dfs(is, i, l, m+1) dfs(i+1, ie, m, r) } dfs(0, row, 0, col) return res } // 给定一个 n 行 m 列的矩阵. // minI=argmin_j(A[i][j]) 单调递增时, 返回 minI. // get(i, j) : 返回 A[i][j] 的函数 func MonotoneMinima2(row, col int, get func(i, j int) int) []int { f := func(i, j, k int) bool { return get(i, j) <= get(i, k) } return MonotoneMinima(row, col, f) } // 寻找[start,end)中的一个极值点,不要求单峰性质. // // 返回值: (极值点,极值) func FibonacciSearch(f func(x int) int, start, end int, minimize bool) (int, int) { end-- a, b, c, d := start, start+1, start+2, start+3 n := 0 for d < end { b = c c = d d = b + c - a n++ } get := func(i int) int { if end < i { return INF } if minimize { return f(i) } return -f(i) } ya, yb, yc, yd := get(a), get(b), get(c), get(d) for i := 0; i < n; i++ { if yb < yc { d = c c = b b = a + d - c yd = yc yc = yb yb = get(b) } else { a = b b = c c = a + d - b ya = yb yb = yc yc = get(c) } } x := a y := ya if yb < y { x = b y = yb } if yc < y { x = c y = yc } if yd < y { x = d y = yd } if minimize { return x, y } return x, -y }