#include #pragma GCC optimize("Ofast") #pragma GCC optimize("unroll-loops") using namespace std; using std::cout; using std::cin; using std::endl; using ll=long long; using ld=long double; const ll ILL=167167167167167167; const int INF=100000000; const int mod=998244353; #define rep(i,a,b) for (int i=(int)(a);i<(int)(b);i++) #define all(p) p.begin(),p.end() template using _pq = priority_queue, greater>; template ll LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template ll UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,const T &b){if(a>b){a=b;return 1;}else return 0;} template bool chmax(T &a,const T &b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} void yneos(bool a,bool upp=0){if(a) cout<<(upp?"YES\n":"Yes\n"); else cout<<(upp?"NO\n":"No\n");} template void vec_out(vector &p,int ty=0){ if(ty==2){cout<<'{';for(int i=0;i<(int)p.size();i++){if(i){cout<<",";}cout<<'"'< T vec_min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T vec_max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T vec_sum(vector &a){assert(!a.empty());T ans=a[0]-a[0];for(auto &x:a) ans+=x;return ans;} int pop_count(long long a){int res=0;while(a){res+=(a&1),a>>=1;}return res;} using len_type=ll; struct edge{ int to; len_type length; }; len_type dijkstra_movement(edge e,int from,len_type t){ return t+e.length; } vector dijkstra(vector> &G,int start,len_type inf){ int M=G.size(); assert(M>start&&start>=0); vector seen(M,inf); seen[start]=0; priority_queue,vector>,greater>> pq; pq.push({0,start}); while(!pq.empty()){ len_type time; int ver; tie(time,ver)=pq.top(); pq.pop(); if(seen[ver]>t; rep(i,0,t) solve(); } void solve(){ int N,M; cin>>N>>M; vector> G(N),H(N); rep(i,0,M){ int a,b; ll c; cin>>a>>b>>c; a--,b--; G[a].push_back({b,c}); H[b].push_back({a,c}); } auto f=[&](int ind,vector> &g) -> vector { return dijkstra(g,ind,ILL); }; auto A=f(N-2,G),B=f(N-2,H); auto C=f(N-1,G),D=f(N-1,H); rep(k,0,N-2){ ll ans1=B[k]+A[N-1]+C[k]; ll ans2=D[k]+C[N-2]+A[k]; ll ans=min(ans1,ans2); if(ans>=ILL) cout<<"-1\n"; else cout<