#include <bits/stdc++.h>
using namespace std;
using ll = long long;

int main(){
    ll t; cin >> t;
    while (t--) {
        ll n, x; cin >> n >> x;
        if (n * (n + 1) / 2 <= x) {
            for (ll i = 1; i < n; i++) cout << i << " ";
            cout << n + x - n * (n + 1) / 2 << endl;
        }
        else cout << -1 << endl;
    }
    
    
    
    return 0;
}