use std::io::stdin;

const INF: usize = 1000000000;

fn main() {
    let mut input = stdin().lines().map(|s| s.unwrap());
    let s = input.next().unwrap();
    let mut s = s.split_whitespace();
    let n: usize = s.next().unwrap().parse().unwrap();
    let m: usize = s.next().unwrap().parse().unwrap();

    let mut x = Vec::with_capacity(n);
    let mut a = Vec::with_capacity(n);
    let mut b = Vec::with_capacity(n);
    for line in input.take(n) {
        let mut line = line.split_whitespace();
        let xi: usize = line.next().unwrap().parse().unwrap();
        let ai: usize = line.next().unwrap().parse().unwrap();
        let bi: usize = line.next().unwrap().parse().unwrap();
        x.push(xi);
        a.push(ai);
        b.push(bi);
    }
    let mut x = x;
    let a = a;
    let b = b;

    let mut by_a: Vec<_> = (0..n).collect();
    by_a.sort_by_key(|&i| a[i]);
    let by_a = by_a;
    let mut by_b: Vec<_> = (0..n).collect();
    by_b.sort_by_key(|&i| b[i]);
    let by_b = by_b;

    let mut res = INF;
    let mut two = 0;
    let mut three = 0;
    for xi in &mut x {
        // のちのループが sa = 0, sb = max から始まるので、全員がちょうど xi + 1 個の問題を解ける
        *xi += 1;

        if *xi >= 2 {
            two += 1;
        }
        if *xi >= 3 {
            three += 1;
        }
    }

    let mut by_a_i = 0;
    let mut by_b_i = 0;
    let mut sb = 100001;
    for sa in 0..100002 {
        while by_a_i < n && a[by_a[by_a_i]] < sa {
            let i = by_a[by_a_i];
            x[i] -= 1;
            if x[i] == 1 {
                two -= 1;
            }
            if x[i] == 2 {
                three -= 1;
            }
            by_a_i += 1;
        }

        while two < m && sb > 0 {
            sb -= 1;
            while by_b_i < n && b[by_b[n - 1 - by_b_i]] >= sb {
                let i = by_b[n - 1 - by_b_i];
                x[i] += 1;
                if x[i] == 2 {
                    two += 1;
                }
                if x[i] == 3 {
                    three += 1;
                }
                by_b_i += 1;
            }
        }
        // println!("sa: {}, sb: {}, t: {}", sa, sb, three);
        if two >= m {
            res = res.min(three);
        }
    }

    println!("{}", res);
}