#include <bits/stdc++.h>
using ll = long long;
#define rep(i, n) for (int i = 0, i##_len = (n); i < i##_len; ++i)
#define reps(i, n) for (int i = 1, i##_len = (n); i <= i##_len; ++i)
#define rrep(i, n) for (int i = ((int)(n)-1); i >= 0; --i)
#define rreps(i, n) for (int i = ((int)(n)); i > 0; --i)
#define rep2(i, s, n) for (int i = (s); i < (int)(n); i++)
#define repc2(i, s, n) for (int i = (s); i <= (int)(n); i++)
constexpr int inf = 2000'000'000;
constexpr ll linf = 4000000000000000000ll;
constexpr ll M7 = 1000000007ll;
constexpr ll M09 = 1000000009ll;
constexpr ll M9 = 998244353ll;
#define all(v) begin(v), end(v)
#define rall(v) rbegin(v), rend(v)
using namespace std;
template <typename T>
inline ostream& operator<<(ostream& os, const vector<T>& v) {
    for (auto itr = v.begin(); itr != v.end(); ++itr) {
        os << *itr;
        if (itr != v.end() - 1) {
            os << " ";
        }
    }
    return os;
}
template <typename T, typename U>
std::ostream& operator<<(std::ostream& os, const std::pair<T, U>& p) noexcept {
    return os << "(" << p.first << ", " << p.second << ")";
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    int n;
    string s;
    cin >> n >> s;
    vector<ll> a(2 * n);
    rep(i, 2 * n) cin >> a[i];

    vector<vector<ll>> dp = vector<vector<ll>>(2 * n, vector<ll>(2 * n, linf));
    for (int len = 2; len <= 2 * n; len += 2) {
        for (int l = 0; l < 2 * n; l++) {
            int r = l + len - 1;
            if (r >= 2 * n) break;
            if (len == 2) {
                ll x = 0;
                if (s[l] == ')') x += a[l];
                if (s[r] == '(') x += a[r];
                dp[l][r] = x;
            } else {
                for (int i = l + 1; i < r; i += 2) dp[l][r] = min(dp[l][r], dp[l][i] + dp[i + 1][r]);
                ll x = 0;
                if (s[l] == ')') x += a[l];
                if (s[r] == '(') x += a[r];
                dp[l][r] = min(dp[l][r], x + dp[l + 1][r - 1]);
            }
        }
    }
    cout << dp[0][2 * n - 1] << endl;

    return 0;
}