# 全部でN個の順位がある、その数字を削除したときに、次の数字が削除した数字より小さければ最前、逆なら最後尾

N, K = map(int, input().split())
A = list(map(int, input().split()))

updown = [0]*N

for i in range(N-2, -1, -1):
    if A[i]==A[i+1]:
        updown[i] = updown[i+1]
    elif A[i]<A[i+1]:
        updown[i] = 1
    elif A[i]>A[i+1]:
        updown[i] = -1

first = 1
last = N
for i in range(N):
    if updown[i] == 0:
        remove = i
        break
    elif updown[i] == 1:
        if last == K:
            remove = i
            break
        else:
            last -= 1
    elif updown[i] == -1:
        if first == K:
            remove = i
            break
        else:
            first += 1
#print(remove)

ans = []
for i in range(N):
    if i != remove:
        ans.append(A[i])
print(*ans)