#include using namespace std; using ll = long long; const ll modc = 1e9+7; class mint { ll x; public: mint(ll x=0) : x((x%modc+modc)%modc) {} mint operator-() const { return mint(-x);} mint& operator+=(const mint& a) { if ((x += a.x) >= modc) x -= modc; return *this; } mint& operator-=(const mint& a) { if ((x += modc-a.x) >= modc) x -= modc; return *this; } mint& operator*=(const mint& a) { (x *= a.x) %= modc; return *this; } mint operator+(const mint& a) const { mint res(*this); return res+=a; } mint operator-(const mint& a) const { mint res(*this); return res-=a; } mint operator*(const mint& a) const { mint res(*this); return res*=a; } mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } mint inv() const {return pow(modc-2);} mint& operator/=(const mint& a){ return (*this) *= a.inv();} mint operator/(const mint& a) const { mint res(*this); return res/=a; } bool operator == (const mint& a) const{ return x == a.x;} bool operator != (const mint& a) const{ return x != a.x;} friend ostream& operator<<(ostream& os, const mint& m){ os << m.x; return os; } friend istream& operator>>(istream& ip, mint &m) { ll t; ip >> t; m = mint(t); return ip; } ll val(){ return x;} }; void solve(){ ll N; mint a, x, b, y, c, z, ans=0; cin >> N >> a >> x >> b >> y >> c >> z; a /= x; b /= y; c /= z; ans -= a.pow(N) * 2; ans -= b.pow(N) * 2; ans -= c.pow(N) * 2; ans += (a + b).pow(N); ans += (b + c).pow(N); ans += (c + a).pow(N); cout << mint(1)-ans << endl; } int main(){ cin.tie(nullptr); ios_base::sync_with_stdio(false); int T; cin >> T; while(T){ T--; solve(); } return 0; }