#include using namespace std; #define ll long long #define all(x) x.begin(),x.end() #define rep(i,a,b) for(int i=a;i<=b;i++) #define rep_r(i,a,b) for(int i=a;i>=b;i--) #define each(a,x) for (auto& x : a) using pi = pair; using pl = pair; using vi = vector; using vl = vector; #define fi first #define se second #define sz(x) int(x.size()) #define so(x) sort(all(x)) #define so_r(x) sort(all(x),greater()) #define zero(x) memset(x,0,sizeof(x)) #define pb push_back #define lb lower_bound #define ub upper_bound const char nl = '\n'; int dx[4] = {1,-1,0,0}; int dy[4] = {0,0,1,-1}; int bit_cnt(int x){ return __builtin_popcount(x); } ll bex(ll a, ll b, ll mod = 1e9 + 7){ll res = 1LL; while(b){ if (b&1) res = res * a % mod; a = a * a % mod; b >>= 1;} return res;} template bool chmax(t&a,u b){if(a bool chmin(t&a,u b){if(b= MOD) v -= MOD; return *this; } mi& operator-=(const mi& m) { if ((v -= m.v) < 0) v += MOD; return *this; } mi& operator*=(const mi& m) { v = v*m.v%MOD; return *this; } mi& operator/=(const mi& m) { return (*this) *= inv(m); } friend mi pow(mi a, ll p) { mi ans = 1; assert(p >= 0); for (; p; p /= 2, a *= a) if (p&1) ans *= a; return ans; } friend mi inv(const mi& a) { assert(a.v != 0); return pow(a,MOD-2); } mi operator-() const { return mi(-v); } mi& operator++() { return *this += 1; } mi& operator--() { return *this -= 1; } mi operator++(int) { v++; if (v == MOD) v = 0; return mi(v); } mi operator--(int) { v--; if (v < 0) v = MOD-1; return mi(v); } friend mi operator+(mi a, const mi& b) { return a += b; } friend mi operator-(mi a, const mi& b) { return a -= b; } friend mi operator*(mi a, const mi& b) { return a *= b; } friend mi operator/(mi a, const mi& b) { return a /= b; } friend ostream& operator<<(ostream& os, const mi& m) { os << m.v; return os; } friend istream& operator>>(istream& is, mi& m) { ll x; is >> x; m.v = x; return is; } }; mi a[N], pref[N]; void solve(){ int n; cin >> n; int p; cin >> p; a[1] = 0, a[2] = 1; rep(i,3,n) a[i] = (p * a[i - 1] + a[i-2]); mi ans = 0, cur = 0; rep(i,1,n){ cur += a[i]; ans += a[i] * cur; } cout << ans << nl; } int main(){ ios_base::sync_with_stdio(false); cin.tie(NULL); int t = 1; //cin >> t; while (t--){ solve(); } }