#include <bits/stdc++.h>

using namespace std;
using ll = long long;

const ll modc = 1e9+7;
class mint {
    ll x;
public:
    mint(ll x=0) : x((x%modc+modc)%modc) {}
    mint operator-() const { return mint(-x);}
    mint& operator+=(const mint& a) {
        if ((x += a.x) >= modc) x -= modc;
        return *this;
    }
    mint& operator-=(const mint& a) {
        if ((x += modc-a.x) >= modc) x -= modc;
        return *this;
    }
    mint& operator*=(const  mint& a) {
        (x *= a.x) %= modc;
        return *this;
    }
    mint operator+(const mint& a) const {
        mint res(*this);
        return res+=a;
    }
    mint operator-(const mint& a) const {
        mint res(*this);
        return res-=a;
    }
    mint operator*(const mint& a) const {
        mint res(*this);
        return res*=a;
    }
    mint pow(ll t) const {
        if (!t) return 1;
        mint a = pow(t>>1);
        a *= a;
        if (t&1) a *= *this;
        return a;
    }
    mint inv() const {return pow(modc-2);}
    mint& operator/=(const mint& a){ return (*this) *= a.inv();}
    mint operator/(const mint& a) const {
        mint res(*this);
        return res/=a;
    }
    bool operator == (const mint& a) const{ return x == a.x;}
    bool operator != (const mint& a) const{ return x != a.x;}
    friend ostream& operator<<(ostream& os, const mint& m){
        os << m.x;
        return os;
    }
    friend istream& operator>>(istream& ip, mint &m) {
        ll t;
        ip >> t;
        m = mint(t);
        return ip;
    }
    ll val(){ return x;}
};

int main(){
    cin.tie(nullptr);
    ios_base::sync_with_stdio(false);

    int H, W, T, r, c;
    mint P=1;
    cin >> H >> W;
    vector v(H, vector<ll>(W));
    for (int i=0; i<H; i++){
        for (int j=0; j<W; j++){
            cin >> v[i][j];
            P *= v[i][j];
        }
    }
    vector<mint> h(H, 1), w(W, 1);
    for (int i=0; i<H; i++){
        for (int j=0; j<W; j++) h[i] *= v[i][j];
    }
    for (int i=0; i<W; i++){
        for (int j=0; j<H; j++) w[i] *= v[j][i];
    }

    cin >> T;
    while(T){
        T--;
        cin >> r >> c; r--; c--;
        cout << P / (h[r] * w[c]) * v[r][c] << '\n';
    }

    return 0;
}