#!/usr/bin/python3

N, M = map(int,input().split())

A = list(map(int,input().split()))
A.reverse()
for i in range(M):
    A[i] -= 1

# 二次元表現の頂点を一次元にする
def vnum(i, j):
    return j * N + i

# N * (M + 1) のグリッドを作る
adj = [[] for _ in range(N * (M + 1))]

# 横の双方向の辺を張る
for i in range(N - 1):
    for j in range(M + 1):
        adj[vnum(i, j)].append((vnum(i + 1, j), 1))
        adj[vnum(i + 1, j)].append((vnum(i, j), 1))

# 縦 / クロスの辺を張る
for j in range(M):
    a = A[j]
    for i in range(N):
        if a == i:
            adj[vnum(i, j)].append((vnum(i + 1, j + 1), 0))
            continue
        if a == i-1:
            adj[vnum(i, j)].append((vnum(i - 1, j + 1), 0))
            continue
        adj[vnum(i, j)].append((vnum(i, j + 1), 0))

# ダイクストラする
from heapq import heappush, heappop
def dijkstra(s, adj):
    n = len(adj)
    dist = [float('inf')] * n
    dist[s] = 0
    que = [(0, s)]
    while que:
        d, v = heappop(que)
        if dist[v] != d:
            continue
        for w, cost in adj[v]:
            if dist[v] + cost < dist[w]:
                dist[w] = dist[v] + cost
                heappush(que, (dist[w], w))
    return dist

dist = dijkstra(vnum(0, 0), adj)

ans = []
for i in range(1, N):
    ans.append(dist[vnum(i, M)])

print(*ans)