//yukicoder@cpp17

#include <iostream>
#include <iomanip>

#include <algorithm>

#include <cmath>
#include <cctype>
#include <climits>
#include <cassert>

#include <string>
#include <vector>
#include <set>
#include <stack>
#include <queue>
#include <map>

#include <random>

#include <bitset>

#include <complex>

#include <utility>

#include <numeric>

#include <functional>


using namespace std;
using ll = long long;
using P = pair<ll,ll>;

const ll MOD = 998244353;
const ll MODx = 1000000007;
const int INF = (1<<30)-1;
const ll LINF = (1LL<<62LL)-1;
const double EPS = (1e-10);

P ar4[4] = {{0,1},{0,-1},{1,0},{-1,0}};
P ar8[8] = {{-1,-1},{-1,0},{-1,1},{0,-1},{0,1},{1,-1},{1,0},{1,1}};




template <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }
template <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }
 
/*
確認ポイント
cout << fixed << setprecision(n) << 小数計算//n桁の小数表記になる

計算量は変わらないが楽できるシリーズ
min(max)_element(iter,iter)で一番小さい(大きい)値のポインタが帰ってくる
count(iter,iter,int)でintがiterからiterの間にいくつあったかを取得できる
*/

/* comment outed because can cause bugs
__attribute__((constructor))
void initial() {
  cin.tie(0);
  ios::sync_with_stdio(false);
}
*/

vector<vector<int>> A;
vector<int> vis;
vector<pair<int,int>> ans;
int dfs(int n, int r = 0){
  int fromLeaf = 0;
  for(int i = 0; A[n].size() > i; i++){
    if(!vis[A[n][i]]){
      vis[A[n][i]] = 1;
      if(fromLeaf) fromLeaf = min(fromLeaf, dfs(A[n][i], r+1));
      else fromLeaf = dfs(A[n][i], r+1);
    }
  }
  ans[n].first = r;
  ans[n].second = fromLeaf;
  return fromLeaf+1;

}

int main(){
  int n;cin>>n;
  A.assign(n, vector<int>());
  vis.assign(n, 0);
  ans.assign(n, {-1,-1});
  for(int i = 0; n-1 > i; i++){
    int u,v;cin>>u>>v;u--;v--;
    A[u].push_back(v);
    A[v].push_back(u);
  }

  vis[0] = 1;
  dfs(0);
  for(int i = 0; n > i; i++){
    cout << min(ans[i].first, ans[i].second)<< endl;
  }
  return 0;
}