#include #include #include #include using namespace std; const long long Target = 500000000000000000LL; void Operation(vector& A, vector& B, int idx1, int idx2) { long long avg1 = (A[idx1] + A[idx2]) / 2LL; long long avg2 = (B[idx1] + B[idx2]) / 2LL; A[idx1] = avg1; B[idx1] = avg2; A[idx2] = avg1; B[idx2] = avg2; } int main() { // Step 1. 入力 vector A(50, 0); vector B(50, 0); long long N; cin >> N; for (int i = 0; i < N; i++) cin >> A[i] >> B[i]; // Step 2. 最初のステップ long long MinV = (1LL << 60); long long MinID = -1; for (int i = 1; i < N; i++) { long long v1 = (A[0] + A[i]) / 2LL; long long v2 = (B[0] + B[i]) / 2LL; long long err = max(abs(v1 - Target), abs(v2 - Target)); if (MinV > err) { MinV = err; MinID = i; } } Operation(A, B, 0, MinID); // Step 3. ランダム貪欲 vector> Answer; int StartTime = clock(); long long RecordScore = Target; while (clock() - StartTime < 9 * CLOCKS_PER_SEC / 10) { vector C = A; vector D = B; long long RemainC = Target * 2 - C[0]; long long RemainD = Target * 2 - D[0]; vector Used(N, false); vector Order; Order.push_back(0); // 貪欲法スタート while (true) { vector> Vec; for (int i = 1; i < N; i++) { if (Used[i] == true) continue; long long v1 = abs(RemainC - C[i]); if (v1 >= RemainC) continue; long long v2 = abs(RemainD - D[i]); if (v2 >= RemainD) continue; Vec.push_back(make_pair(max(v1, v2), i)); } sort(Vec.begin(), Vec.end()); if (Vec.size() == 0) break; int idx = Vec[rand() % max(1, min(3, (int)Vec.size() / 3))].second; RemainC = min(6LL * Target, 2LL * RemainC - C[idx]); RemainD = min(6LL * Target, 2LL * RemainD - D[idx]); Order.push_back(idx); Used[idx] = true; } for (int i = 1; i < N; i++) { if (Used[i] == false) Order.push_back(i); } // スコアを出す vector> CurrentAns; CurrentAns.push_back(make_pair(0, MinID)); for (int i = N - 2; i >= 0; i--) { CurrentAns.push_back(make_pair(Order[i], Order[i + 1])); Operation(C, D, Order[i], Order[i + 1]); } // スコアを比較 long long CandScore = max(abs(Target - C[0]), abs(Target - D[0])); if (RecordScore > CandScore) { RecordScore = CandScore; Answer = CurrentAns; } } // Step 5. 出力 cout << Answer.size() << endl; for (int i = 0; i < Answer.size(); i++) cout << Answer[i].first + 1 << " " << Answer[i].second + 1 << endl; return 0; }