#include using namespace std; #define FOR(i,m,n) for(int i=(m);i<(n);++i) #define REP(i,n) FOR(i,0,n) using ll = long long; constexpr int INF = 0x3f3f3f3f; constexpr long long LINF = 0x3f3f3f3f3f3f3f3fLL; constexpr double EPS = 1e-8; constexpr int MOD = 998244353; // constexpr int MOD = 1000000007; constexpr int DY4[]{1, 0, -1, 0}, DX4[]{0, -1, 0, 1}; constexpr int DY8[]{1, 1, 0, -1, -1, -1, 0, 1}; constexpr int DX8[]{0, -1, -1, -1, 0, 1, 1, 1}; template inline bool chmax(T& a, U b) { return a < b ? (a = b, true) : false; } template inline bool chmin(T& a, U b) { return a > b ? (a = b, true) : false; } struct IOSetup { IOSetup() { std::cin.tie(nullptr); std::ios_base::sync_with_stdio(false); std::cout << fixed << setprecision(20); } } iosetup; template std::vector> enumerate_quotients(const T n) { std::vector> quotients; for (T l = 1; l <= n;) { const T quotient = n / l, r = n / quotient + 1; quotients.emplace_back(l, r, quotient); l = r; } return quotients; } int main() { constexpr int M = 1000000; array memo{}; FOR(i, 1, M + 1) memo[i] = memo[i - 1] + 1. / i; const auto f = [&](const ll r) -> long double { return r <= M ? memo[r] : logl(r + 1) + (r + 1.L) / (2LL * (r + 1)) + 0.07721566490153286060651209L; }; ll n; cin >> n; long double ans = 0; for (const auto& [l, r, q] : enumerate_quotients(n)) { ans += (f(r - 1) - f(l - 1)) * f(q); } cout << ans << '\n'; return 0; }