# それまでに出てきた約数までの最高歩数+1すればいいのでは

def divisors(n):
    lower_divisors , upper_divisors = [], []
    i = 1
    while i*i <= n:
        if n % i == 0:
            lower_divisors.append(i)
            if i != n // i:
                upper_divisors.append(n//i)
        i += 1
    return lower_divisors + upper_divisors[::-1]

N = int(input())
A = list(map(int, input().split()))

div_count = [0]*(10**5+3)

for a in A:
    divs = divisors(a)
    mx = 0
    for d in divs:
        mx = max(mx, div_count[d])
    div_count[a] = mx+1
    
ans = max(div_count)
print(ans)

#print(div_count[:40])