#include <bits/stdc++.h>
#include <atcoder/modint>
using namespace std;
using ll = long long;
using mint = atcoder::modint998244353;

int N;
ll M;
int X[201010];
ll Sf[201010], Sb[201010];
mint mpow(mint a, ll b){
    if(b == 0)return 1;
    mint r = 1;
    while(b){
        if(b & 1)r = r * a;
        a = a * a;
        b >>= 1;
    }
    return r;
}
void solve(){
    cin >> N >> M;
    int c = 0;
    Sf[0] = Sb[N - 1] = 0;
    for(int i = 0;i < N;i++){
        cin >> X[i];
        c += (X[i] == -1);
    }
    for(int i = 0;i < N;i++){
        Sf[i] += X[i];
        Sf[i + 1] = Sf[i];
    }
    for(int i = N - 1;i > 0;i--){
        Sb[i - 1] = X[i] + Sb[i];
    }
    if(c == 0){
        int ans = N;
        for(int i = 0;i < N;i++){
            ans -= (Sf[i] % M) == 0;
        }
        cout << (Sf[N - 1] % M == 0 ? ans : 0) << "\n";
        return;
    }
    if(c == 1){
        ll s = 0;
        ll k = (M - (Sf[N - 1] + 1) % M) % M;
        int ans = N;
        for(int i = 0;i < N;i++){
            s += (X[i] == -1 ? k : X[i]);
            s %= M;
            ans -= (s == 0);
        }
        cout << ans << "\n";
        return;
    }
    mint ans = mpow(M, c - 1) * N;
    int nc = 0;
    for(int i = 0;i < N;i++){
        if(X[i] == -1){
            nc++;
            c--;
        }
        mint f = (nc == 0 ? Sf[i] % M == 0 : mpow(M, nc - 1));
        mint g = ( c == 0 ? Sb[i] % M == 0 : mpow(M,  c - 1));
        ans -= f * g;
    }
    cout << ans.val() << "\n";
}
int main(void){
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    
    int t; cin >> t;
    while(t--)solve();
    return 0;
}