#include //#include using namespace std; #define lli long long int #define REP(i, s, n) for (lli i = s; i < n; i++) #define INF (1LL << 62) #define mp(a, b) make_pair(a, b) #define SORT(V) sort(V.begin(), V.end()) #define PI (3.141592653589794) #define TO_STRING(VariableName) #VariableName #define LOG1(x) \ if (DEBUG) \ cout << TO_STRING(x) << "=" << x << " " << endl; #define LOG2(x, y) \ if (DEBUG) \ cout << TO_STRING(x) << "=" << x << " " << TO_STRING(y) << "=" << y << endl; #define LOG3(x, y, z) \ if (DEBUG) \ cout << TO_STRING(x) << "=" << x << " " << TO_STRING(y) << "=" << y << " " \ << TO_STRING(z) << "=" << z << endl; #define LOG4(w, x, y, z) \ if (DEBUG) \ cout << TO_STRING(w) << "=" << w << " " << TO_STRING(x) << "=" << x << " " \ << TO_STRING(y) << "=" << y << " " << TO_STRING(z) << "=" << z \ << endl; #define LOG5(w, x, y, z, a) \ if (DEBUG) \ cout << TO_STRING(w) << "=" << w << " " << TO_STRING(x) << "=" << x << " " \ << TO_STRING(y) << "=" << y << " " << TO_STRING(z) << "=" << z << " " \ << TO_STRING(a) << "=" << a << endl; #define LOG6(w, x, y, z, a, b) \ if (DEBUG) \ cout << TO_STRING(w) << "=" << w << " " << TO_STRING(x) << "=" << x << " " \ << TO_STRING(y) << "=" << y << " " << TO_STRING(z) << "=" << z << " " \ << TO_STRING(a) << "=" << a << " " << TO_STRING(b) << "=" << b \ << endl; #define overload6(a, b, c, d, e, f, g, ...) g #define LOG(...) \ overload6(__VA_ARGS__, LOG6, LOG5, LOG4, LOG3, LOG2, LOG1)(__VA_ARGS__) template bool chmax(T &a, const T &b) { if (a < b) { a = b; return 1; } return 0; } template bool chmin(T &a, const T &b) { if (b < a) { a = b; return 1; } return 0; } mt19937 engine; std::chrono::system_clock::time_point start, endTime; std::ostream &operator<<(std::ostream &dest, __int128_t value) { std::ostream::sentry s(dest); if (s) { __uint128_t tmp = value < 0 ? -value : value; char buffer[128]; char *d = std::end(buffer); do { --d; *d = "0123456789"[tmp % 10]; tmp /= 10; } while (tmp != 0); if (value < 0) { --d; *d = '-'; } int len = std::end(buffer) - d; if (dest.rdbuf()->sputn(d, len) != len) { dest.setstate(std::ios_base::badbit); } } return dest; } __int128 parse(string &s) { __int128 ret = 0; for (int i = 0; i < s.length(); i++) { if ('0' <= s[i] && s[i] <= '9') { ret = 10 * ret + s[i] - '0'; } } return ret; } #define DEBUG 0 // checker https://atcoder.jp/contests/abc264/tasks/abc264_e struct UnionFind { vector par; // par[i]:iの親の番号 (例) par[3] = 2 : 3の親が2 vector isOk; vector siz; // 素集合のサイズを表す配列(1 で初期化) lli N; UnionFind(int N) : par(N), isOk(N), siz(N) { //最初は全てが根であるとして初期化 for (int i = 0; i < N; i++) { par[i] = i; isOk[i] = false; siz[i] = 1; } this->N = N; } int root(int x) { // データxが属する木の根を再帰で得る:root(x) = {xの木の根} if (par[x] == x) return x; return par[x] = root(par[x]); } void setOk(lli i) { isOk[i] = isOk[root(i)] = true; } bool isCheckOk(lli i) { return isOk[root(i)]; } void unite(int x, int y) { // xとyの木を併合 int rx = root(x); // xの根をrx int ry = root(y); // yの根をry if (rx == ry) return; // xとyの根が同じ(=同じ木にある)時はそのまま if (siz[rx] < siz[ry]) swap(rx, ry); siz[rx] += siz[ry]; par[ry] = rx; // xとyの根が同じでない(=同じ木にない)時:xの根rxをyの根ryにつける if (isOk[rx] || isOk[ry]) { isOk[ry] = true; isOk[rx] = true; } } bool same(int x, int y) { // 2つのデータx, yが属する木が同じならtrueを返す int rx = root(x); int ry = root(y); return rx == ry; } lli size(lli x) { return siz[root(x)]; } }; lli color[110]; void solve() { // write your code here lli N, M; cin >> N >> M; vector A(M), B(M); vector> G(N); REP(i, 0, M) { cin >> A[i] >> B[i]; A[i]--; B[i]--; G[A[i]].push_back(B[i]); G[B[i]].push_back(A[i]); } REP(i, 0, N) color[i] = -1; REP(i, 0, N) { if (color[i] != -1) continue; queue q; q.push(i); color[i] = 0; while (q.size()) { lli now = q.front(); q.pop(); for (auto next : G[now]) { if (color[next] == -1) { color[next] = 1 - color[now]; q.push(next); } else { if (color[next] == color[now]) { cout << "No" << endl; return; } } } } } cout << "Yes" << endl; } // Generated by 2.13.0 https://github.com/kyuridenamida/atcoder-tools (tips: // You use the default template now. You can remove this line by using your // custom template) int main() { // Failed to predict input format lli N = 1; // cin >> N; while (N--) solve(); return 0; }