#include using namespace atcoder; #include #pragma GCC optimize("O3") //#pragma GCC optimize("unroll-loops") #define rep(i, n) for(ll i = 0; i < n; i++) #define rep2(i, m, n) for(ll i = m; i <= n; i++) #define rrep(i, m, n) for(ll i = m; i >= n; i--) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define MAX(x) *max_element(all(x)) #define MIN(x) *min_element(all(x)) #define SZ(a) ((ll)(a).size()) #define bit(n, k) ((n >> k) & 1) using namespace std; using ll = long long; using P = pair; const int dx[4] = { -1, 0, 1, 0}; const int dy[4] = { 0, 1, 0, -1}; const int inf = 1e9 + 7; const ll infll = 1e18; //const double pi = acos(-1); using Graph = vector>; using REV_PQ = priority_queue, greater>; using PQ = priority_queue; const int SIZE = 400010; ll powll(ll n, ll x) { // return n ^ x; ll ret = 1; rep(i, x) ret *= n; return ret; } ll ceil(ll x, ll m){ if(m < 0) x = -x, m = -m; if(x >= 0) return (x + m - 1) / m; else return x / m; } ll floor(ll x, ll m){ if(m < 0) x = -x, m = -m; if(x >= 0) return x / m; else return (x - m + 1) / m; } void OutputYesNo(bool val) { if (val) cout << "Yes" << endl; else cout << "No" << endl; } void OutputTakahashiAoki(bool val) { if (val) cout << "Takahashi" << endl; else cout << "Aoki" << endl; } void OutPutInteger(ll x) { cout << x << endl; } void OutPutString(string x) { cout << x << endl; } int pop_count(ll n){ int ret = 0; while(n > 0){ if(n % 2 == 1) ret++; n /= 2; } return ret; } bool inrange(ll from, ll to, ll val){ // from <= val <= to であれば、trueを返す return from <= val && val <= to; } using PAIR_REV_PQ = priority_queue, vector>, greater>>; //typedef atcoder::modint998244353 mint; //typedef atcoder::modint1000000007 mint; //typedef modint mint; //typedef vector ModintVec; //typedef vector> t; while(t--){ int n; cin >> n; vector p(n); rep(i, n){ cin >> p[i]; p[i]--; } ll ans = 0; deque res; fenwick_tree ft(n); rep(i, n){ if(ft.sum(0, p[i] + 1) < ft.sum(p[i] + 1, n)){ res.push_front(p[i]); ans += ft.sum(0, p[i] + 1); }else{ res.push_back(p[i]); ans += ft.sum(p[i] + 1, n); } ft.add(p[i], 1); } cout << ans << endl; for(auto v : res) cout << v + 1 << " "; cout << endl; } }