#pragma GCC optimize("O2") #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define int ll #define INT128_MAX (__int128)(((unsigned __int128) 1 << ((sizeof(__int128) * __CHAR_BIT__) - 1)) - 1) #define INT128_MIN (-INT128_MAX - 1) #define clock chrono::steady_clock::now().time_since_epoch().count() #ifdef DEBUG #define dbg(x) cout << (#x) << " = " << x << '\n' #else #define dbg(x) #endif namespace R = std::ranges; namespace V = std::views; using namespace std; using ll = long long; using ull = unsigned long long; using ldb = long double; using pii = pair; using pll = pair; //#define double ldb template ostream& operator<<(ostream& os, const pair pr) { return os << pr.first << ' ' << pr.second; } template ostream& operator<<(ostream& os, const array &arr) { for(const T &X : arr) os << X << ' '; return os; } template ostream& operator<<(ostream& os, const vector &vec) { for(const T &X : vec) os << X << ' '; return os; } template ostream& operator<<(ostream& os, const set &s) { for(const T &x : s) os << x << ' '; return os; } signed main() { ios::sync_with_stdio(false), cin.tie(NULL); int t; cin >> t; while(t--) { int n, m; cin >> n >> m; vector l(n), r(n); for(int &x : l) cin >> x; for(int &x : r) cin >> x; if (accumulate(l.begin(), l.end(), 0ll) <= m and m <= accumulate(r.begin(), r.end(), 0ll)) { int mx = *R::partition_point(V::iota(0, m + 1), [&](int x) { int cnt = 0; for(int i = 0; i < n; i++) cnt += min(max(l[i], x), r[i]); return cnt < m; }); for(int i = 0; i < n; i++) l[i] = max(l[i], mx - 1); int sum = accumulate(l.begin(), l.end(), 0ll); for(int i = 0; i < n; i++) if (sum < m and l[i] == mx - 1 and l[i] < r[i]) l[i]++, sum++; int ans = m * (m - 1) / 2; for(int x : l) ans -= x * (x - 1) / 2; cout << ans << '\n'; } else { cout << -1 << '\n'; } } return 0; }