#include <iostream>
#include <map>
#include <vector>

using namespace std;

constexpr int iINF = 1'000'000'000;

int main () {
    int N; cin >> N;
    vector<int> A(N);
    for (int i = 0; i < N; i++) cin >> A[i];

    // 全体のxorが0という必要条件 -> 最初にチェックしておけば片側の存在を示せばOK
    // ダブり -> 即OK

    bool ok = true;
    int XOR = 0;

    for (auto a : A) XOR ^= a;

    if (XOR != 0) ok = false;

    map<int, int> mp;
    for (auto a : A) mp[a]++;

    const int MAX = 10000;
    vector<int> possible(MAX + 1, iINF);

    bool first = true;

    for (auto v : mp) {
        if (v.second % 2 == 0) {
            cout << "Yes\n";
            return 0;
        }

        if (first) {
            first = false;
            possible[v.first] = 1;
            continue;
        }

        for (int i = 0; i <= MAX; i++) {
            if (!possible[i] == iINF) continue;
            possible[i ^ v.first] = min(possible[i ^ v.first], possible[i] + 1);
        }
    }

    if (N <= possible[0]) ok = false;

    if (ok) {
        cout << "Yes\n";
    }
    else {
        cout << "No\n";
    }
}