N,M=map(int, input().split())
A=list(map(int, input().split()))
dp=[[1000]*N for _ in range(N)]
#dp[i][j]:iの荷物をjに持ってくるのに必要な最小回数
for i in range(N):
  dp[i][i]=0
now=10**10
for i in range(N):
  for j in range(1,N):
    dp[i][j]=min(dp[i][j],dp[i][j-1]+1)
  for j in range(N-2,-1,-1):
    dp[i][j]=min(dp[i][j],dp[i][j+1]+1)
    
for a in A:
  for i in range(N):
    dp[i][a-1],dp[i][a]=dp[i][a],dp[i][a-1]
  for j in range(1,N):
    dp[i][j]=min(dp[i][j],dp[i][j-1]+1)
  for j in range(N-2,-1,-1):
    dp[i][j]=min(dp[i][j],dp[i][j+1]+1)

ans=[]
for i in range(1,N):
  ans.append(dp[i][0])
print(*ans)