#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using namespace atcoder;
using ll = long long;

int N, A[101010];
ll M, S, sum = 0;

int main() {
  cin >> N >> M >> S;
  for (int i = 0; i < N; i++) {
    cin >> A[i];
    sum += A[i];
  }
  if (abs(S - sum) % M == 0) cout << "Yes" << endl;
  else cout << "No" << endl;
  return 0;
}