#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using namespace atcoder;
using ll = long long;

int T, N, A[202020];
ll sum;

void solve() {
  cin >> N;
  for (int i = 1; i <= N; i++) { 
    cin >> A[i];
    sum += A[i];
  }
  if (sum % 3 == 0 && *max_element(A, A + N) <= sum / 3) cout << "Yes" << endl;
  else cout << "No" << endl;
}

int main() {
  cin >> T;
  while (T--) solve();
  return 0;
}